Thread: How to find the nth number?

What is the program about?

This program has 2 tasks.
One is to print all the even numbers from 0 to 100
Second is to enter a number between 1 to 10 and have the program print every nth number between 0 and 100. For example, if you enter 5 then 0, 5, 10, 15, 20 .. 95, 100 is printed.

What is the problem?

I already completed task one. And second task I think I am almost done is to print the nth number but I need the formula that finds the nth number.
So how can that be done.

import java.util.Scanner;
public class EvenNums {
public static void main( String args[])
{
int evenNum=2;
int number;
int i;
Scanner s = new Scanner(System.in);
for(evenNum=2;evenNum<=100;evenNum+=2)
System.out.print(evenNum + " "); 
 
System.out.print("\nEnter a number between 1 to 10 to get nth result:"); 
    number = s.nextInt();
    while (number >= 1 && number <= 10) 
      for (i=0; i<=100; i++){
 
 
 
{
System.out.println(number);
}
}
}
}

How about multiplying N by K to find what is N-th number with step of size K?

More commonly it is a "linear dependence". You always can find a formula if you have only two values for it (for example 5 for N=1 and 15 for N=3). I've once tried to provide a small exercise on that topic at my site: Linear Function

Why do you need to do any multiplication?

To find N-th number with step of size K one can either add K to starting value N times or simply multiply one by another. What's wrong?