Thread: help with necklace problem?

So the program begins with two single digit numbers. The next number is obtained by adding the first two numbers together and saving only the ones digit. This process is repeated until the necklace closed by returning to the original two numbers. For example, starting from the two numbers 1 and 8, we get: 1 8 9 7 6 3 9 2 1 3 4 7 1 8

Here's what I have so far:

import java.util.Scanner;
 
class test {
	public static void main(String args[]){
		Scanner input = new Scanner(System.in);
 
		int num1,num2,sum;
 
 
    	System.out.print("Enter the first starting number: ");
		num1 = input.nextInt();
 
		System.out.print("Enter the second starting number: ");
		num2 = input.nextInt();
 
 
		int sum1 = num1+num2;
		int total = sum1 + num2;
 
		int ones = total %10;
 
		System.out.print(num1 + " ");
		System.out.print(num2 + " ");
		System.out.print(sum1+ " ");
		System.out.print(ones+ " ");
 
 
	}
}

I got the basic algorithm right, but now I need to put this in a loop. How would I do it?

So you need to know when to stop looping. Any ideas how you might do that?

no, and btw I'm new to java programming.