Thread: I have a question.

Could someone please explain to me why my program keeps giving me the following error when I try to read in a text file (test.txt). I placed the text file into the same folder as the .java file. Also, I am using netbeans if it matters. Thank you.

Error message:

Exception in thread "main" java.io.FileNotFoundException: test.txt (The system cannot find the file specified)
at java.io.FileInputStream.open(Native Method)
at java.io.FileInputStream.<init>(FileInputStream.jav a:138)
at java.io.FileInputStream.<init>(FileInputStream.jav a:97)
at java.io.FileReader.<init>(FileReader.java:58)
at linearcongruentialgenerator.LinearCongruentialGene rator.main(LinearCongruentialGenerator.java:25)
Java Result: 1

Here is my code:

package linearcongruentialgenerator;
 
//Imports
import java.io.*;
import java.util.*;
 
/**
 *
 * @author Jared
 */
public class LinearCongruentialGenerator {
 
    /**
     * @param args the command line arguments
     */
    public static void main(String[] args) throws FileNotFoundException, IOException {
        String fileName;
        int Z, I, M, Seed;
 
        Scanner s = new Scanner(System.in);
        System.out.println("Whay is the name of the file?");
        fileName = s.nextLine();
 
        BufferedReader inputFile = new BufferedReader(new FileReader(fileName));
        String[] line;
 
        while (inputFile.ready()) {
            line = inputFile.readLine().split(" ");
            Z = Integer.parseInt(line[0]);
            I = Integer.parseInt(line[1]);
            M = Integer.parseInt(line[2]);
            Seed = Integer.parseInt(line[3]);
 
            int period = period(Z, I, M, Seed);
 
            System.out.println("Case #1: " + period);
 
 
 
            /*  Test
             LinearCongruentialGenerator result  = new LinearCongruentialGenerator(3,2,10,5);
             int answer = result.getAnswer();
             System.out.println(answer);
 
             System.out.println(result.next());
             System.out.println(result.next());
             System.out.println(result.next());
             System.out.println(result.next());
             System.out.println(result.next());
             System.out.println(result.next());
             System.out.println(result.next());
 
             int period = period(533, 250, 314322, 7052);
 
             System.out.println("\n" + period);
             */
        }
    }
    //Variables 
    int Z, I, M, Seed, N, answer;
 
    /**
     *
     * @param z
     * @param i
     * @param m
     * @param seed
     */
    public LinearCongruentialGenerator(int z, int i, int m, int seed) {
 
        //These three are the constants.
        Z = z;
        I = i;
        M = m;
 
        //This is the seed.
        Seed = seed;
 
        //The generator:
        N = (Z * Seed + I) % M;
 
        answer = N;
 
    }
 
    public int next() {
        LinearCongruentialGenerator temp = new LinearCongruentialGenerator(Z, I, M, N);
 
        this.N = temp.answer;
 
        return temp.answer;
    }
 
    public static int period(int z, int i, int m, int seed) {
 
        //Variables
        int Z, I, M, Seed, N1, N2 = 0;
        int period = 0;
        Z = z;
        I = i;
        M = m;
        Seed = seed;
 
        LinearCongruentialGenerator temp = new LinearCongruentialGenerator(Z, I, M, Seed);
 
        N1 = temp.answer;
 
        while (N1 != N2) {
            N2 = temp.next();
            period++;
        }
 
        return period;
 
    }
 
    public int getAnswer() {
        return answer;
    }
}

Here are the contents of my text file.

3 2 10 5

FileNotFoundException will mean that it cannot find the file or it doesn't exist in that directory.

What is the path to your file?
What are you typing in for your input?

the path can be relative to the root of your project. For example, if you create a folder name textfiles in your root directory, the path will be;
"textfiles/somefile.txt"

Alternatively you can pass the complete path like;
"C:\\somefolder\\maybeAnotherFolder\\somefile. txt"

I am simply entering test.txt

The actual path to the text file is C:\Users\Jared\Desktop\Linear Congruential Generator\LinearCongruentialGenerator\src\linearco ngruentialgenerator

--- Update ---

C:\Users\Jared\Desktop\Linear Congruential Generator\LinearCongruentialGenerator\src\linearco ngruentialgenerator\test.txt

--- Update ---

And the path to my .java file is C:\Users\Jared\Desktop\Linear Congruential Generator\LinearCongruentialGenerator\src\linearco ngruentialgenerator\LinearCongruentialGenerator.ja va

This is what it printed: Where are we=C:\Users\Jared\Desktop\Linear Congruential Generator\LinearCongruentialGenerator\Here I Am

--- Update ---

This is the example that I am going by:

public class Input{
    public static void main (String[] args)
        throws FileNotFoundException, IOException 
    {
        BufferedReader inputFile = new BufferedReader(new FileReader("test.txt"));
 
        while (inputFile.ready()) {
            String[] line = inputFile.readLine().split(" ");
            String name = line[0];
            int id = Integer.parseInt(line[1]);
 
 
            System.out.printf("%d - %s\n", id, name);       
        }
    }
}

Im just not understanding as to why it is not finding the file.

Okay, so I moved the text file to the folder that it said it was looking in and it gave me this error:

Exception in thread "main" java.io.FileNotFoundException: test.txt (The system cannot find the file specified)
at java.io.FileInputStream.open(Native Method)
at java.io.FileInputStream.<init>(FileInputStream.jav a:138)
at java.io.FileInputStream.<init>(FileInputStream.jav a:97)
at java.io.FileReader.<init>(FileReader.java:58)
at linearcongruentialgenerator.LinearCongruentialGene rator.main(LinearCongruentialGenerator.java:25)
Java Result: 1

--- Update ---

I fixed that issue, it was saved as test.txt.txt
Thanks for the help.