Thread: Integer to String, can't get it to work

Hi.
I try to get the following code to run:

for (int i = 0; i < 1; i++) {
			str = Integer.toString(i);
			if (i < 10) {
				str = "0" + str;
			}
 
 
			for (int j = 0; j < 1; j++) {
				str2 = Integer.toString(j);
				if (j < 10) {
					str2 = "0" + str2;
 
				}
				strfinal = str2+str;
				grid2.add(strfinal);
 
			}
		}

As you can see, I will only add 1 value to grid2, which is the String 0000. But when I compare it to "0000" I get a 'false' return. Can someone please help me out? Thank you.

Are you aware that your for loops only run once with the value 0? Also, for string equality tests use:

if (str.equals(str2))

Originally Posted by ChristopherLowe

Are you aware that your for loops only run once with the value 0? Also, for string equality tests use:

if (str.equals(str2))

Yeah, I'm aware of that. I only changed it to see if I could find the error. The thing is that I want the output to act like a string, so I can use it in another class. Why can't I do it like that?

I don't understand. Integer.toString(i) returns the string representing the integer 'i'. What is the error and what are you expecting?

Originally Posted by ChristopherLowe

I don't understand. Integer.toString(i) returns the string representing the integer 'i'. What is the error and what are you expecting?

Ok. I will implement this in a djikstra algorithm. I have a "from", "current" and "to" that consists of a string of 4 numbers. Then I will check, each timestep, what my current node is, whether or not I'm there yet etc. So basically I want a fast way to add nodes to a 100*100 grid, and I'd prefer to not have to do it manually. This is where the loops come in.

--- Update ---

You can see the loops on the top of the page, where I add 0000 to grid2.

grid.add("0000");

System.out.println(grid2.get(0) + " " + grid.get(0));
System.out.println(grid2.get(0) == grid.get(0));

This will give:

0000 0000
false

Originally Posted by Norm

The == operator says that the two references in the expression do not refer to the same object.
== does not look at the contents of two objects. The equals() method does that.

--- Update ---

Another waste of time helping an OP that has cross posted:
Integer to String, can't get it to work

Thanks a lot for the reply. It's just that I have a deadline so I wanted to increase the chances of me getting an answer. I really appreciate it!

Originally Posted by Norm

In the future please post links to the other sites where you have posted the same question.

Okay, sorry.