Thread: print A-Z without O I J

char[]chr=new char[21];
	int i=0; chr[0]='A';
	for(i=1; i<20 && chr[i]!='I' && chr[i]!='O' && chr[i]!='J';i++){
		chr[i]=++(chr[i-1]);}
		System.out.println(Arrays.toString(chr));

I want to print charactor from A-Z without I O J; above is my code.
and the result is [B, C, D, E, F, G, H, I, J, K, L, M, N, O, P, Q, R, S, T, T,
would any one pls tell me why
1, i assigment char[0] as 'A' out of for loop, why chr[0] is B?
2 and most confused me, why STILL have I O J????
THANK YOU!

int i=0; chr[0]='A';

What is the very next thing that happens to this variable 'i'?

ok, i have a type mistake, should be
int i
and i assign as 1 in for loop.

i am amateur. i try to use if statement, but i can't.
Soooo nice if any one could help.

How would you do it without a computer. Write out your steps in plain language on paper and be specific. Once you have that try and write these steps/tests as code.

Keep the loop simple. Let it count only. Do all of your conditional tests in the body of the loop.

Originally Posted by Norm

	for(i=1; i<20 && chr[i]!='I' && chr[i]!='O' && chr[i]!='J';i++){
		chr[i]=++(chr[i-1]);

Where did you get that code? It doesn't look like what a beginner would write.

What do you want for the contents of the array? Show what the first 15 elements would be.

thank you for you reply. i have fingerout my problem. i used ++(chr[i-1]), then ,when programs runs, chr0-> chr1, and it changged itslef also.