Thread: Hangman multiple letters

indexOf() only returns the first occuring letter,

There is another version of the indexOf() method that will start its search at another column besides column 0.
Use that version with the column past where the last match was found. If found at 8 start next search at 9

You need to save the last value returned by indexOf to use in the next search.
If you find the first "a" at 1, then start the next search for an "a" at 2

Something like this:
find first one and save the column: int ix = str.indexOf("a")
look for the next one starting at that saved column+1
int ix2 = str.indexOf("a", ix+1);

Use a single loop to iterate over each char in secretWord. If the char matches the guess letter then change the dash in the updatedWord to the guess letter at the same index.

Or you could use replaceAll.

loop each char in secretWord {
    if char at index equals guess {
        change dash to guess in updatedWord
    }
}

Since the code needs to continue looking for a letter until it is not found, code would need a loop.
You could use a 0 for the starting column for the indexOf() search for the first search.

I used the word column as if the String were a row made up of columns. The first column is the first position in the String at index=0.

Maybe tomorrow the light will come on.

Originally Posted by JavaN3wbie

okay i can't do it. i've been at it the entire day and i still can't figure out how to put everything together
oh well, thanks for helping

Even with the pseudocode I provided above? All you have to do is convert it to actual code using calls to methods in the String class.