Thread: Hi everyone i stuck at something and i need a little help please

We started to learn classes and i created this method :

 public static Student[] getStudentArray(Student[] arr){
		 Scanner s=new Scanner(System.in);
		 String Name;float Avg;
 
		 for (int i=0;i<arr.length;i++){
			 System.out.println("name?");
			 Name=s.nextLine();
 
			 System.out.println("avg?");
			 Avg=s.nextFloat();
			 Student temp=new Student(Name,Avg); 
			 arr[i]=temp;
		 }
 
 
		return arr; 
 
 
	 }

Student is my class.the problem is that the output looks like that:"console":
How many students?
2
name?
john
avg?
20
name?
avg?

then as you can see it goes name?avg? and stuck.what have i done wrong?

Originally Posted by Norm

The problem is with the way the Scanner class buffers the keyboard input. The lineend is not removed by the nextFloat() method. The next nextLine() reads just that lineend.
Solution: call nextLine() after nextFloat() to clear the lineend.

Thanks but it still gives me trouble.i need to create an array that contains String(needed nextline) and integers.
but the momonet i want to print my array the data conataine string is empty!
something like this (from console):

Please enter how many Employees:
1
Please enter Employee's #1 id:
1
Please enter Employee's #1 name:
john
Please enter Employee's #1 salary:
1000
Original array from user:
1  1000

As you can see the data of the string return empty!

--- Update ---

this what my array's method contain :

  Name=s.nextLine();
 
		   temp.setname(Name);
		   s.nextLine();
		   System.out.println("Please enter Employee's #"+(i+1)+" salary:");
		   Salary=s.nextInt();
		   temp.setsalary(Salary);
 
		   arr[i]=temp;

I need to create array and input value in this order:int id(integer),String name(must be nextline),int salary(integer).
i fount that if i do s.nextline after the name=s.nextline it fix this.
however when it comes to print my array it consider the String argument as a blanket area.
example :"id:2333 salary:23"without Name(string)in the middle.

could anyone know how can i solve this?:[

Originally Posted by Norm

Does the code read the endline character out of Scanner's buffer by calling the nextLine() method after calls to the other next methods?
Can you Post the complete code that shows when each of the Scanner's methods are called?

This my code:

Scanner s=new Scanner(System.in);
	   int Id=0;String Name="";int Salary=0;
 
 
	   for (int i=0;i<arr.length;i++){
 
		   Employee temp=new Employee(Id,Name,Salary);
		   System.out.println("Please enter Employee's #"+(i+1)+" id:");
		   Id=s.nextInt();
		   temp.setid(Id);
		   System.out.println("Please enter Employee's #"+(i+1)+" name:");
		   Name=s.nextLine();
		   temp.setname(Name);
 
		   System.out.println("Please enter Employee's #"+(i+1)+" salary:");
		   Salary=s.nextInt();
		   temp.setsalary(Salary);
 
		   arr[i]=temp;
	   }
	   return arr;

--- Update ---

Originally Posted by eyalfish

This my code:

Scanner s=new Scanner(System.in);
	   int Id=0;String Name="";int Salary=0;
 
 
	   for (int i=0;i<arr.length;i++){
 
		   Employee temp=new Employee(Id,Name,Salary);
		   System.out.println("Please enter Employee's #"+(i+1)+" id:");
		   Id=s.nextInt();
		   temp.setid(Id);
		   System.out.println("Please enter Employee's #"+(i+1)+" name:");
		   Name=s.nextLine();
		   temp.setname(Name);
 
		   System.out.println("Please enter Employee's #"+(i+1)+" salary:");
		   Salary=s.nextInt();
		   temp.setsalary(Salary);
 
		   arr[i]=temp;
	   }
	   return arr;

P.s i did try to make s.nextline; after Name=s.nextline. however as i said when i wanted to print my array the console get blanket area when the string should output.

You are a king!!!!!!!!!!!!!!!
thank you thank you:]