Thread: Again i need some advice please

Sorry to bother you that much.
I have a project that contain an array of people(each index contain name,salary and id number).
i need to make a matrix that each name will be in a new row.
so i did count how many different names i have(this is what will be my matrix size).
but i am not sure how to continue ,any ideas?

example:"console" -this is my array:{
1 james bond 1000
2 tami 400
3 james bond 500
4 tami 1
5 james bond 1} first-id,second-name,third-salary.{5 indexes}

i need to make matrix (for this example will be): { james bond james bond james bond
tami tami}
hope that you understood if not nvm but thanks for any help

Originally Posted by Norm

Is that a 2 dim String array? Can you post code that shows how it is defined? It needs "s and , to show what the elements in the array are.


That looks like a one dim array? Is that correct?

Is the content of the one dim array copied from the first column of the 2 dim array?

You know what lets say i have an array of strings{"james","john","james","john","james"}

I need to initialize a matrix that each row contain a different name.

--- Update ---

The output will be a matric look like that: john john john
james james

--- Update ---

3 times james***
2 times john.

Each in sep row .

	int arr[]=new int[]{1,1,1,2,2};
 
 
    int row=2;  //two different number=two rows
	int[][]matrix=new int[row][];
    for (int i=0;i<matrix.length;i++){
    	for(int j=0;j<matrix[i].length;j++){
 
 
    	}
    }

I stuck on how do i apply this via matrix to get in one row (3 times '1'): 1 1 1
and second row(different number '2') : 2 2

yes it is sorted.
i need to make a matrix from this array -each row different number and the times the number occuered
1.i need to check how many numbers are different to determine how many rows i need(i check and i need 2 rows)
2.and here is where i am stuck , i need to make a matrix from that(i hope you understand).
here is what i'v tried so far but the program fail:

	int arr[]=new int[]{1,1,1,2,2};
 
    int row=2;
	int[][]matrix=new int[row][];
	for (int i=0;i<row;i++){
		for(int j=0;j<arr.length;j++){
			if(arr[i]!=arr[i+1]){
				matrix[i][j]=arr[i];
			}
		}
 
 
 
	}

yes for array of example like i show{1 1 1 2 2}

to matrix like that: 1 1 1
2 2


i count the number of different number=2.that's the row number.
but how can i continue from their?can you show me the right way?or direct me.
i am completely lost here