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on unary operators
DIFFERENCE BETWEEN THESE TWO PROGRAMS PLEASE EXPLAIN ME IN DETAIL HOW IT WORKS
public class a
{
public static void main(String[] args)
{
int i=0;
int j=i++ +i++ + i + i;
System.out.println(i);
System.out.println(j);
}
}
AND
public class B
{
public static void main(String[] args)
{
int i=0;
int j=i++ + i + i + i++;
System.out.println(i);
System.out.println(j);
}
}
Related threads:
Re: on unary operators
Please read this topic to learn how to post code in code or highlight tags and other useful info for newcomers..
These two lines:
int j=i++ +i++ + i + i;
int j=i++ + i + i + i++;
are different. What about the differences don't you understand or about the results caused by them?
Re: on unary operators
am getting different outputs and i ve doubt how i value is passing pls clear my doubt
Re: on unary operators
Write down:
(first line without unary operator)
j = i + i + i + i
substitute 0 for i, calculate j. Shat does j equal?
write down (or modify the line in the program) to:
j = i++ + i + i + i
substitute 0 for i. what does that equal?
write down (or modify the line in the program) to:
j = i++ + i++ + i + i
Keep going until YOU figure it out. You don't need anyone's help with adding together numbers less than 5.
Re: on unary operators
Another way to see what each expression evaluates to and when it returns its value is to use println statements:int i = 1; // set initial value System.out.println("i++="+i++); // show value returned by i++ System.out.println("i="+i); // show value AFTER i++
If you don't understand my answer, don't ignore it, ask a question.
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