Thread: Catch block problem. Please fix my problem.

hi friend,

you can use the while with in try and catch block like this,

private int guess()
{
int line=0;                                      //chaned the datatype
try
{
while (true)
{
 
System.out.print("Your guess: ");
line = Integer.parseInt(in.readLine());  //Here i parse the string to int in a single statment
 
}
 
}
catch (Exception e){                   //Here is given only Exception instead of IOException
System.out.println("That's not even a number!: " + e);
}
return line;                                //Here i put return type
}

It may work.

Thanks,

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.Random;
 
 
public class Demo
{
	private int target;
	private BufferedReader in;
 
	public Demo()
	{
		Random rand;
 
		rand = new Random();
		target = 1 + rand.nextInt(10);
		in = new BufferedReader (new InputStreamReader (System.in));
	}
 
	private int guess() throws Exception
	{
		int line;
		while (true)
		{
 
				System.out.print("Your guess: ");
				line = Integer.parseInt(in.readLine());
				return (line);
		}
 
	}
 
	public void play()
	{
		int num;
 
		try
		{
		num = guess();
		while (num != target)
		{
			if (num < target)
				System.out.println("Higher");
			else if (num > target)
				System.out.println("Lower");
			num = guess();
		}
		System.out.println("You got it!");
		}
		catch(Exception e)
		{
			System.out.println("That's not even a number! ");
		}
 
	}
 
	public static void main(String args[])
	{
		Demo game;
		game = new Demo();
		System.out.println("Guess a number between 1 and 10");
		game.play();
	}
}

--- Update ---

Please do study code.