Thread: Experiencing problems w/ Scanner & main, open to any assistance!

At the moment, I am creating this program to ask the user for input. The user will give a number (to be added to sum and then divided by n to find the mean) or the letter "e" (to terminate the program). The program should take multiple numbers until an "e" is given.

This is the underlying concept but I'm not really there yet. I'm having some trouble getting my main and Scanner to cooperate so any help would be appreciated, thank you.

//package homework1;
 
import java.util.Scanner;
 
public class hmwk1 
{
    public static void main(String[] args) 
	{
		partA();
	}
 
	public static void partA()
    {  
        int n = 0;
        double mean = 0;
        double sum = 0;
        String input;
 
 
        System.out.println("Enter a number or enter 'e' to quit:");
        Scanner kb = new Scanner(System.in);
        input = kb.next();
 
        while(!(input.equals("e")))
        {
        	if(!(input.equals("e")))
        	{
                double d = Double.parseDouble(input);
 
                if(d >= 10 && d <= 100)
                {
                    sum += d;
                    n++;  
                }
                else
                {
                    System.out.println("Not in range");
                }  
        	}
 
            /*System.out.println("Enter a number or enter 'e' to quit:");
            String input2 = kb.next();
            if(!input2.equals("e"))
            {
                double d = Double.parseDouble(input);
            }*/
        }
            mean = sum / n;
            System.out.println(mean);
 
            System.exit(0);
    }
 
}

Are you getting errors? Please post those. Also, not sure what you mean about cooperation of main and Scanner. The main() calls a method and steps aside. (Give your methods better names that describe what they do, usually verbs.)

Hi,

As per your program, Your problem is

If i entered "e" means you are trying to parse into double that time you are getting NaN.
if i entered number means program hanged in infinite loop.

So you can do one thing,

1)Put the while as a continuous running.
2)get the input inside the while loop.
3)If press "e" means but break and come out of while loop then perform your calculation.

while(true)
{
input = kb.next();
      if(**your codition**)
     {
 
      }
      else
           break;
}

Still you facing difficulties, post here

Thanks,

Hello all,

After making modifications suggested by Ganeprog, I am still struggling to compile the program. In essence, the program does generate the output question but when a user inputs a number my program blows up. Here is my error message, I'm using CompileOnline at the moment because I am away from my PC.

Exception in thread "main" java.util.NoSuchElementException
at java.util.Scanner.throwFor(Scanner.java:907)
at java.util.Scanner.next(Scanner.java:1416)
at hmwk1.partA(hmwk1.java:25)
at hmwk1.main(hmwk1.java:9)

And here is my updated Java code;

//package homework1;
 
import java.util.Scanner;
 
public class hmwk1 
{
    public static void main(String[] args) 
    {
		partA();
	}
 
	public static void partA()
    {  
        int n = 0;
        double mean = 0;
        double sum = 0;
        String input;
 
 
        System.out.println("Enter a number or enter 'e' to quit:");
        Scanner kb = new Scanner(System.in);
 
        while(true)
        {
            input = kb.next();
 
        	if(!(input.equals("e")))
        	{
                double d = Double.parseDouble(input);
 
                if(d >= 10 && d <= 100)
                {
                    sum += d;
                    n++;  
                }
                else
                {
                    System.out.println("Not in range");
                    break;    
                }
        	}
 
 
        }
            mean = sum / n;
            System.out.println(mean);
 
            System.exit(0);
    }
 
}

The objective of this program is to

• ask the user for a number or an 'e' to exit. Each time the user enters a number and presses "return", the program will prompt the user to enter another number or press 'e'.
• When user presses 'e' and and hits return, the program will calculate the mean (m) of the numbers entered
• Range [10,100]
• If a number is entered that is not in that range, print an error message and then continue on with the program until they enter "e"

@ GregBrannon I do not have the option to name the methods.

Thanks for ANY assistance, really.

Perhaps your code formatting is confusing you, but what you describe and what your code says don't match.

This is what your code says:

get input
for other than "e"
turn input into double value
and if double value is between 10 and 100, inclusive,
add value to sum and increment count
otherwise print error message and exit input loop

There's no code that exits on an "e" input. In fact, an "e" input is just ignored.

I would suggest using nextLine() as it will clear the buffer. A lot of problems arise when using next() and then not clearing the buffer afterwards.

Thanks for all of your feedback thus far. I am now coding the final section of the program and my objective is to create the last method "partD" to print the following output to a file named "report.txt";

Number of Entries: 5
Numbers entered: 1,2,3,5,6
Mean: 3.4
Maximum Number Found: 6
Minimum Number Found: 1

I was thinking I should add a double array to input the values after I parsed them. Then I would be able to use a function to determine the minimum and maximum values.

The PartD method is the only relevant method to my question. It is the last method in the program. I am seeking logical guidance, I'm unfamiliar with the approach I should take to gather the input and print it and also analyzing it for high and low value.

Here is my code;

package homework1;
 
import java.io.FileNotFoundException;
import java.io.PrintWriter;
import java.io.Writer;
import java.util.Scanner;
 
public class hmwk1 
{
    private static Scanner kb;
	private static Scanner kb2;
	private static Scanner kb3;
 
	private static PrintWriter outputStream;
 
	public static void main(String[] args) 
    {
		partD();
	}
 
	public static void partA()
    {  
        int n = 0;
        double mean = 0;
        double sum = 0;
        String input;
 
 
        System.out.println("Enter a number or enter 'e' to quit:");
        kb = new Scanner(System.in);
 
 
        while(! (input = kb.next()).equalsIgnoreCase("e") )
        {
 
                double d = Double.parseDouble(input);
 
                if(d >= 10 && d <= 100)
                {
                    sum += d;
                    n++;  
                }
                else
                {
                    System.out.println("Not in range");
                    break;
                }  
        }
 
 
            mean = sum / n;
            System.out.println(mean);
 
            System.exit(0);
    }
 
	public static void partB()
    {  
        int n = 0;
        double mean = 0;
        double sum = 0;
        String input;
 
        String fileName = "out5555.txt";
        try {
			outputStream = new PrintWriter(fileName);
 
		} catch (FileNotFoundException e) {
			// TODO Auto-generated catch block
			e.printStackTrace();
		}
 
        System.out.println("Enter a number or enter 'e' to quit:");
 
        kb2 = new Scanner(System.in);
 
        while(! (input = kb2.next()).equalsIgnoreCase("e") )
        {
        		outputStream.println(input);
 
                double d = Double.parseDouble(input);
 
 
                if(d >= 10 && d <= 100)
                {
                    sum += d;
                    n++;  
                }
                else
                {
                    System.out.println("Not in range");
                    break;
                }  
        }
 
            mean = sum / n;
            System.out.println(mean);
 
            outputStream.close();
            System.exit(0);
    }
 
	public static void partC()
    {  
        int n = 0;
        double mean = 0;
        double sum = 0;
        String input;
 
        String fileName = "out1212.txt";
        try {
			outputStream = new PrintWriter(fileName);
 
		} catch (FileNotFoundException e) {
			// TODO Auto-generated catch block
			e.printStackTrace();
		}
 
        System.out.println("Enter a number or enter 'e' to quit:");
 
        kb3 = new Scanner(System.in);
 
        outputStream.println("Numbers entered:");
 
        while(! (input = kb3.next()).equalsIgnoreCase("e") )
        {
        		outputStream.println(input);
 
                double d = Double.parseDouble(input);
 
                if(d >= 10 && d <= 100)
                {
                    sum += d;
                    n++;  
                }
                else
                {
                    System.out.println("Not in range");
                    break;
                }  
        }
 
 
 
 
            mean = sum / n;
            System.out.println(mean);
 
            outputStream.println("Average:" + mean);
            outputStream.close();
 
            System.exit(0);
    }
	public static void partD()
    {  
        int n = 0;
        double mean = 0;
        double sum = 0;
        String input;
 
        String fileName = "report.txt";
        try {
			outputStream = new PrintWriter(fileName);
 
		} catch (FileNotFoundException e) {
			// TODO Auto-generated catch block
			e.printStackTrace();
		}
 
        System.out.println("Enter a number or enter 'e' to quit:");
 
        kb3 = new Scanner(System.in);
 
        outputStream.print("Numbers entered: ");
 
        while(! (input = kb3.next()).equalsIgnoreCase("e") )
        {
        		outputStream.print(input + ", ");
 
                double d = Double.parseDouble(input);
 
                if(d >= 10 && d <= 100)
                {
                    sum += d;
                    n++;  
                }
                else
                {
                    System.out.println("Not in range");
                    break;
                }  
        }
 
 
 
 
            mean = sum / n;
            System.out.println(mean);
            outputStream.println("  Number of Entries:" + n);
            outputStream.println("Mean:" + mean);
            outputStream.println("Maximum Number Found:");
            outputStream.println("Minimum Number Found:");
 
            outputStream.close();
 
            System.exit(0);
    }
 
 
}

Why does this line appear in the program multiple times?:

System.out.println("Enter a number or enter 'e' to quit:");

I see it's partly because you've set up the program to do each part separately (odd), but anytime you're coding the same thing over and over again, you should think "Method!" Programmers like to think they are efficient, but they're basically lazy, and writing the same code over and over again is offensive. Also, multiple Scanner objects are unnecessary. One for the whole program should do. Focusing on each part separately could have been done in a way that the common methods were written once and shared among the parts.

As for your PartD, what you showed requires storing all values entered by the user into a collection of some kind. Since the program doesn't know how many values the user will enter, an ArrayList is more appropriate than a simple Array. Do you know/can you use an ArrayList? If not, then a sufficiently large Array will be required and the user input will have to be limited in size to the size of the Array. After storing the numbers entered, PartD is simple math and logic.

@GregBrannon

"Programmers like to think they are efficient, but they're basically lazy, and writing the same code over and over again is offensive."

Lol.

Also, multiple Scanner objects are unnecessary (one for entire program) - I resolved this problem, thanks for clarifying.

Focusing on each part separately could have been done in a way that the common methods were written once and shared among the parts. - I'm not experienced enough yet, I think this program was created to be an introductory exercise.

But in conclusion,
I ended up using an ArrayList and I found a very helpful video on Youtube. My problem is resolved, thanks to all who contributed.