Please describe the output of the following program!

**sgt98** · February 9th, 2014, 10:30 AM

I have seen this interview question on a site and executed it

code:

public class Main
{
public static void main(String l[])
{
String a,b;
a="First";
b="Second";
swap(a,b);
System.out.println(a);
System.out.println(b);
}
private static void swap(String a, String b)
{
String temp=a;
a=b;
b=temp;
}
}

The output is:
First
Second

but i was expecting
Second
First

can any one explain how??

**Norm** · February 9th, 2014, 11:03 AM

Java passes args by value not reference. The swap method changed the values of the args it received, not the values of the variables whose values were passed to it.

**Ganeprog** · February 11th, 2014, 01:47 AM

Hi,

As norm said you changed only args values. So better you do one thing put print statement with in swap method.

private static void swap(String a, String b)
{
String temp=a;
a=b;
b=temp;
System.out.println(a);
System.out.println(b);
}
}

Thanks,

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