Thread: Can someone help me with this error?

The while loop keeps running although I type quit. What is wrong with this code?

import java.util.*;
 
public class OddEvenGame {
   public static void main(String[] args) {
      Scanner console = new Scanner(System.in);
      Random r = new Random();
 
      int chips = 30;
      int betting = 0;
      String call = "";
      String answer = "";
 
      while (chips != 0 || !answer.equals("quit")) {
         int dice = r.nextInt(6) + 1;
         System.out.print("Odd or even? (type \"quit\" to exit) ");
         call = console.next();
         System.out.print("How many chips are you betting? ");
         betting = console.nextInt();
 
         if (dice % 2 == 0 && call.equals("even")) {
            chips = betting * 2 + chips;
            System.out.println("You have earned " + betting * 2 + " chips!"); 
         } else if (dice % 2 == 1 && call.equals("odd")) {
            chips = betting * 2 + chips;
            System.out.println("You have earned " + betting * 2 + " chips!"); 
         } else {
            chips = chips - betting;
            System.out.println("You lost " + betting + " chips!");
         }
 
        System.out.println("You have " + chips + " chip or chips now.");
        System.out.println();
      }
   }
}

Rethink your while condition. It's better to use '>' and '<' when possible, so change != to >, but then think hard about what the while condition is saying.

I changed != to >, but when I type "quit" to exit, it still runs. shouldn't it stop running because I said !answer.equals("quit")?

I think you never used the variable answer

while (chips != 0 || !answer.equals("quit"))

as what I read in your code, you never write a string in that variable.
and it seems that you code is relying in answer variable to be terminated.

Suggestion:
pls replace your while loop condition with this:
while (chips != 0)

the quit word will be the user's input right?
and you store it in call variable of type string.
therefore the one that your program relied to to terminate is the call variable

pls insert this line of code after call = console.next(); that was the third line in your loop. please insert this

if(call.equalsIgnoreCase("quit")) {
      System.exit(0);
}

System.exit(0); will make your code terminated. and it will check first if the user's input is "quit" (case insensitive since we used equalsIgnoreCase)
when the user's input is "quit" it will terminate your program.
here is the output in mine:

Odd or even? (type "quit" to exit) quit
BUILD SUCCESSFUL (total time: 1 second)