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How would I compare the square of the square root of any number.
How would I compare the square of the square root of any number. The difference in these values is due to the rounding error in Java.
Example: Enter number 2
The answer I should get is: 2.000000000000004
Round off error: -4.440892
The answers are estimated answers but are very close
Related threads:
Re: How would I compare the square of the square root of any number.
Use the standard operators to compare primitives: ==, !=, <, <= etcHow would I compare
If you don't understand my answer, don't ignore it, ask a question.
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