Thread: Replacing characters in a an array

I just came across this post from the forum...is that the only way to code the JOptionPane? Seems rather similar to Sys.out

http://www.javaprogrammingforums.com...ease-help.html



--- Update ---
I had more than this, but post was deleted somehow and this was the gist of it:

WHERE THE HECK DID MY POST GO!!!!!! IS THERE A WAY TO RECOVER??????

for(i = 0 ; i < charArray.length; i++){
				if(Character.isDigit(charArray(i))){
					address.replace("6", "*");
                                        address.replace("7", "*");

Is there a better way to scan a character array for digits and replace any number in the array with another character ("*") in this case? The array is the address, " 1234 Runner Road " .

way to scan a character array for digits and replace

That sounds like something that a regular expression could do if the contents of the array were in a String. I'm no good with regex so I'll leave it to someone that is.
If the values are in an array, then a loop with some if statements would be a way to do it.

Are you working with a String or an array?
With a String I think a regex might work.
With an array, a loop and if statement would do it.

If you are working with an array, you could use a loop, test each element of the array and change that element of the array by assigning it the new value. The code would not use the replace() method.

If you are working with a String, the String class has methods that can scan the String and do replacements using a regex to select which characters to replace.

The code is testing the value of i. That is the int that controls the for loop. It is NOT a char to be tested by the Character class's methods.
Where is the char values that you want to test? Would i be an index into a char array?

Replace is suppose to change the character and assign the new character we prescribe...but it does not.

Read the API doc for the replace() method. It returns a String with the changes.