Thread: Please help me

When it executes, each sentence should be printed on a new line an digits removed. Also, the number of times each vowel appeared. All this should be outputted to the newPassage file.

The while loop inside was changed because I was uncertain. When I run the program the newPassage file stays blank.
Ok, no problem, thanks for the assistance.

Create a Java method nextLarger that accepts two positive integer parameters num and n
and returns the smallest digit within num that is larger than n. For example if num = 3875
and n = 6, your method should return 7. Write a Java program Numbers.java to test the
method.

That was the given question, can someone help with the logic of getting the solution please, I attempted but was unsuccessful.

first, arrange your num in ascending order. if num = 3875 it will be num = 3578 after sorting.,
next start from the lowest, get the number that is higher than n.

Thanks, goin to attempt it now. Back in a 10 mins.

--- Update ---

hi, i know how to put numbers in ascending number but not how to put digits in a number in ascending order.

okay, do you know array?
you can create an array of integer, array of characters will do also.
then use the toCharArray method of String to store it in your array.
then sort it.

ok, back with an attempt in 10 mins

you better paste your code when you back so we can assist you.

int numDigits[] = new int [];

that is invalid declaration. you must put a length on that
Example: int numDigits[] = new int[5];
in your case, you can use the .length() method of String. new int[num.length()]

base on your code, I think it would be better not to use the toCharArray() method, instead we will use the charAt() method.
and we will put that on the int array
Example:
numDigits[i] = ((int) num.charAt(i)) - 48;

as you noticed, I used the (int) to cast the character to integer and subtract 48 to convert in number.

if you a little confused with that algorithm. you can use this
numDigits[i] = Integer.parseInt(Character.toString(num.chartAt(i) ));
parsing the character to string and then to integer.

there's a lot of errors in your code.
okay let's fix 1 by 1.
delete this line first:
Arrays.sort(numDgits []);
int i = num; --you already define the variable i in the loop.
char[] chars = ("" + i).toCharArray();
System.out.printf (%c,numDigits.charAt(i);

if(numDigits.charAt(i) >n)
{
System.out.printf ("%c",numDigits.charAt(i));
}

delete those lines please and paste your new code

public static int nextLarger (int num, int  n){
     int numDigits[] = new int [num.length()];
 
     for(int i=0; i<num.length();i++){
 
	numDigits[i] = ((int) num.charAt(i)) - 48;
 
     }
}

Oh my! ahaha.. Sorry, I did not noticed that the parameter is int. apology.
in your defining the length of array, num.length is invalid syntax. You must parse it first to string.
Integer.toString(num).length() sorry..
since you started with array. let just continue that.
first create a String and declare its value as the String value of num Integer.toString(num)

Miss posted in the group to not use arrays, now checked it lol so now i cant use arrays until she has taught us it well enough. Without arrays what would the code be instead.

Okay, its fine not to use array, it would be easier for you not to use that.
let us start from scratch is it okay with you?
you have this method right?

public static int nextLarger (int num, int  n){
 
}

let us fill that method with codes.

we just need to determine the smallest digit in num that is larger than n,
then we are to need a variable of int, and we are going to put the answer in that int variable.
next I assumed that you already know how to use if statements, a conditional statement and loop.

there are many solutions, is it okay to use while loop in your class? did your teacher taught it already?

yes we did while and if loops

--- Update ---

Yes we can start from scratch, hope we figure it out soon, eyes getting tired lol

Oh my ahaha.
then create a while loop whose condition is num not equal to zero. what is time now in your country? ahaha