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Thread: String Builder questions

  1. #1
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    Default String Builder questions

    When I say:

    StringBuilder strBuilder = new StringBuilder();
           for(char alph = 'a'; alph <= 'z'; alph++)
                {
                    strBuilder.append(alph);
                    System.out.println(strBuilder);
                }

    output:
    "a
    ab
    abc
    abcd..."

    What I want to do now is generate a Char[][] based on user input for the dimensions. Then I will randomly generate characters from the alphabet to fill the array. Should I use the StringBuilder class for this? Or is there a simple way to generate random letters with math.Random?

    That is I know how to generate a random letter between a-z:
    Random r = new Random();
          char c = (char)(r.nextInt(26) + 'a');

    However; i'm not sure how to store those values into a Char[][]. So I figured maybe I could do it with StringBuilder.
    Last edited by vysero; April 13th, 2014 at 05:50 PM.


  2. #2
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    Default Re: String Builder questions

    generate random letters with math.Random
    char are numeric values in the range: 'a' to 'z' and 'A' to 'Z'
    To see the value use an (int) cast: System.out.println((int)'a');
    The Math.random() method can be used in an expression to generate int values in the range: 'a' to 'z' which can be cast to char.

    Or the chars could be put into an array and a random index used to select the elements of the array.
    If you don't understand my answer, don't ignore it, ask a question.

  3. #3
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    Default Re: String Builder questions

    The part that is confusing me is filling my array with the randomly generated letters.

       public Build()
        {
            System.out.println("How many rows?");
            Scanner in = new Scanner(System.in);
            r = in.nextInt();
            System.out.println("How many colums?");
            Scanner in1 = new Scanner(System.in);
            c = in.nextInt();
            char[][] array = new char[r][c];
     
            Random r = new Random();   
            for(int i = 0; i<char[][].length; i++)
               {
                   char y = (char)(r.nextInt(26) + 'a');  
                   char x = (char)(r.nextInt(26) + 'a');
     
                   //how do amend x and y to the char[][] until it is filled with random letters?
               }
        }

  4. #4
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    Default Re: String Builder questions

    Well you will need to iterate through each row and column to achieve that.

    Something like this would work
    for (int i = 0; i < r; i++)
         for (int j = 0; j < c; j++)
              array[i][j] = (char)(r.nextInt(26) + 'a');

  5. The Following User Says Thank You to Parranoia For This Useful Post:

    vysero (April 14th, 2014)

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    Default Re: String Builder questions

    Ah ic okay thank you very much.

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