Thread: Odd and Even numbers with boolean?

Okay, so I'm trying to figure out how to determine if an integer is even or odd by using a boolean method. I think I have the method right, but it's calling the method into the main that has got me stumped. I've been out of practice for a couple weeks, so I'm very confused.

import java.util.Scanner;
 
public class Odd_Even {
	public static void main(String[] args) {
		//Scanner, variables
		Scanner input = new Scanner(System.in);
		int number;
 
		System.out.println("Please enter an integer number: ");
		number = input.nextInt();
 
		//output
		System.out.println("The number " + number + " is " + )
		if(number = iseven(number)) {
 
		}
	}
	private static boolean iseven(int number) {
		if(number % 2 == 0) {
		}
		return true;
 
	}
}

you must have two return statement in iseven method.
check if it is even number using modulo and if it is even return true otherwise return false.

you have only 1 return statement in your method iseven (return true). in that case, it will always returns true even the parameter is odd number.

Alright, so I changed it to:

private static boolean iseven(int number) {
		if(number % 2 == 0) {
			iseven = true;
		}
		else {
			iseven = false;
		}
 
	}

But now it says iseven can't be resolved to a variable, so do I have to make a different variable like

private static boolean iseven(boolean iseven, int number) {
		if(number % 2 == 0) {

But now it says iseven can't be resolved to a variable, so do I have to make a different variable like

because iseven is not defined.
it is either you declare a boolean data whose variable name is iseven before the of-else statement. after the if-else statement return it return iseven;

or

return a boolean expression inside if and else

Nevermind.. I got it. Sorry, I was just being stupid and lazy for that last one.