Thread: Count out program-- How do i do this?

Originally Posted by Norm

Yes it does. The line number is given in the stack trace:

The error is on line 20.


Paste all the lines that define and set values for the code used on line 20.

this is lines 19 and 20

for(count=0;count <= n;++ count){
	kids[count]=1;

Originally Posted by Norm

Did you read posts #18 and 24 about how to code the termination condition in a for loop?

BTW The code should use the array's .length field to test the end of the array, not the variable:n

ok i made some changes and im not getting any errors.However when i enter data nothing happens after that. It just accepts the data and the cursor blinks on the screen

Originally Posted by Norm

Is the code in an infinite loop? To see, add some println() statements inside of the loops. Have them print out the values of the variables that are controlling the looping. The values printed will help you understand what the code is doing.

nothing is working
its due at 6 this evening.

can i use a for loop inside another for loop?
and how do i eliminate a child if im using an array of integers?

Originally Posted by Norm

Use one int value in a slot to show the child is present and have another value to show that the child has been removed. For example: 0 means child is present and 1 means the child has been removed. To eliminate/remove a child, change the slot's contents from 0 to 1.


Yes you can nest as many for loops as needed.

like this?

public static void Remain(int n,int m){
 
int [] kids = new int[n];
 
while(kids[n] !=1){
	for(int j=1;j<=kids.length;j++){
	 for(int i=1;i <=m;i++){
		kids[m] = 0;
		}//end for
		j=m+1;
	}//end for
}
System.out.printf("%d",kids[m]);
}//end method

Originally Posted by Norm

Does it compile? If it does then the code is legal.
There are no comments with the code describing what its logic is supposed to be so it's hard to see if the code is doing what the programmer wants it to do.

it compiles but after i enter the values for the # of children and the # of words it gives out of bounds.

public static void Remain(int n,int m){
 
int [] kids = new int[n];//array int holds total kids
 
while(kids[n] !=1){//while total kids in array is not equal to 1
	for(int j=1;j<=kids.length;j++){//j goes from 1 to maximum kids in array
	 for(int i=1;i <=m;i++){//i goes from 1 to m i.e the amount of words in a sentence
		kids[m] = 0;// mth child eliminated
		}//end for
		j=m+1;//starting with child after the 1 just eliminated
	}//end for
}
System.out.printf("%d",kids[m]);//display the child left
}//end method

Originally Posted by Norm

Where is the stack trace?
That has happened several times in this thread. You should know by now how to fix it.

BTW Most of your comments only say what the code is obviously doing. They should say WHY the code is doing it.

whats is stack trace?

the code is doing it because the question asked to do it. I dont know what else to do. Ill have to submit it as it is.

Originally Posted by Norm

You posted the stack trace in posts#17, 19, 21 and 25

It starts with:
Exception in thread ...
and is followed by several lines that begin with
at ...
at ...

is this close? im getting an infinite loop then my program crashed.

System.out.printf("Enter a number:");
int n = in.nextInt();
System.out.printf("Enter a value for m:");
int m = in.nextInt();
 
int [] nums = new int [n];
while(n !=1){
	int i=1;
for(i=1;i <=n-1;i++) nums[i-1]=i;
for(i=0;i <=m;i++){
	m--;
 
}System.out.printf("%d",nums[i%n]);
	}
}
}

Originally Posted by Norm

No. It looks like a bunch of random code without any meaning.
Post#4 was much closer, but I can not believe you wrote it.

lol.What do i have to do to make post #4 work?

Originally Posted by Norm

Here are a couple of suggestions to start with:
0) fix the formatting so the code is readable
1)Change the variable names from n and m to numKids and numWords to make the code readable
2)Debug it by adding some println statements that print out the values of variables used in the loops.

The Arrays class's toString() method is useful for debugging arrays:
System.out.println("an ID "+ java.util.Arrays.toString(theArrayName));

had to submit it already. We can use those Array.toString yet since the lecturer did not teach it and does not want us implementing things he did not teach.