Thread: count the length of each word in a string

I am looking for a way to create a method with the initial state in while loop, which will count the length of each word in a string using I want the output to be something along the lines of:

hello world how are you
There are 0 words of length 0
There are 0 words of length 1
There are 0 words of length 2
There are 3 words of length 3
There are 0 words of length 4
There are 2 words of length 5

ithis is my code so far it sort of does the job but not the way i want it too

import java.util.Scanner;
import java.util.StringTokenizer;

public class Brown_Matthew_13117002{

public static int count(String s, int len){
int result=0;
StringTokenizer st=new StringTokenizer(s,"[ ,;]");
while(st.hasMoreTokens()){
if(st.nextToken().length()==len){
result++;
}
}
return result;

}

public static void main(String args[])
{
Scanner scan = new Scanner(System.in);
String line ="";
int max = 6;

while((line=scan.nextLine())!=null){
String sentence [] = line.split(" ");
for(int i=0;i<sentence.length;i++) {

System.out.println(sentence[i]);

System.out.println("There are " + count(line, i) + " words of lenghth " + i);


}
}
}
}

the output would end up being
hello
There are 0 words of lenghth 0
world
There are 0 words of lenghth 1
how
There are 0 words of lenghth 2
are
There are 3 words of lenghth 3
you
There are 0 words of lenghth 4

i have no idea how to fix this any h help is appreciated as i am new to java.

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Crossposted here.

After reading the answers the dreamincode users gave, it seems like you just ignored their advice. What is it that you are trying to fix? Go through your code line by line and trace what the program is doing. Your loops, for example, don't cover every case by a long shot. Please make an effort to fix your own code before simply reposting the question.