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Thread: pattern by for loop

  1. #1
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    Default pattern by for loop

    Iam getting output

    222

    44444

    6666666

    888888888

    1010101010101010101010
    I want

    0
    2 4
    6 8 10
    12 14 16 18


    my code is

    class Try7{


    public static void main( String arg[]){
    for(int i=0;i<=10;i++){


    for(int j=0;j<=i;j++){
    if(i%2==0){
    System.out.print(i);
    }

    }
    System.out.println("");
    }

    }
    }
    Last edited by ssonia; August 10th, 2014 at 01:24 AM.


  2. #2
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    Default Re: pattern by for loop

    In that case change your code!
    Improving the world one idiot at a time!

  3. #3
    Member Ada Lovelace's Avatar
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    Default Re: pattern by for loop

    As a starting point, your expected output highest value is 18.
    Your counting only goes as high as 10. If you want the second value
    of every even integer found - you need to change your increment operator
    within your for loop so it counts in 2's.

    Wishes Ada xx
    If to Err is human - then programmers are most human of us all.
    "The Analytical Engine offers a new, a vast, and a powerful language . . .
    for the purposes of mankind
    ."
    Augusta Ada Byron, Lady Lovelace (1851)

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    Default Re: pattern by for loop

    Welcome to the forum! Please read this topic to learn how to post code in code or highlight tags and other useful info for new members.

    Please post your code correctly using code or highlight tags per the above link.

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