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Thread: TreeMap:

  1. #1
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    Default TreeMap:

    I decided to learn a little more about TreeMap and I am having some issues and was hoping for some advice.

    package org.search.BFS;
     
    import java.util.Random;
    import java.util.TreeMap;
     
    public class Graph 
    {
    	protected class node
    	{
    		int number;
    		boolean visited;
    	}
     
    	protected TreeMap<node,Integer> tree = new TreeMap<node,Integer>();
     
    	Graph()
    	{
     
    	}
    	Graph(node s, int v) //constructor
    	{
    		tree.put(s,v);
    	}
     
    	void fillTree()
    	{
    	//fills the graph with 100 random numbers
    	Random random = new Random();
    	//create a new node in method
    	node n = new node();
     
    	for(int i=0;i<=100;i++)
    	{
    		n.number=random.nextInt(100); //add a random number to the node
    		n.visited = false;//set to false inside node
    		n=new node(); //create new node
    		tree.put(n, i);//place node into tree
    	}
     
    	}
     
    	void printTree()
    	{
    		int i =0;
    		while(!tree.isEmpty())
    		{
    			System.out.println(tree.get(i));
    			i++;
    		}
    	}
     
    	public static void main(String [] args)
    	{
    		Graph graph = new Graph();
     
    		graph.fillTree();
    		graph.printTree();
    	}
     
     
    }

     
    errors:
    Exception in thread "main" java.lang.ClassCastException: org.search.BFS.Graph$node cannot be cast to java.lang.Comparable
    	at java.util.TreeMap.compare(TreeMap.java:1188)
    	at java.util.TreeMap.put(TreeMap.java:531)
    	at org.search.BFS.Graph.fillTree(Graph.java:37)
    	at org.search.BFS.Graph.main(Graph.java:56)


  2. #2
    Super Moderator Norm's Avatar
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    Default Re: TreeMap:

    Exception in thread "main" java.lang.ClassCastException: org.search.BFS.Graph$node cannot be cast to java.lang.Comparable
    at java.util.TreeMap.compare(TreeMap.java:1188)
    at java.util.TreeMap.put(TreeMap.java:531)
    at org.search.BFS.Graph.fillTree(Graph.java:37)
    Read the API doc for the put() method. It says it will throw that exception if the node being added cannot be compared. That would mean the class needs to implement Comparable.
    If you don't understand my answer, don't ignore it, ask a question.

  3. #3
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    Default Re: TreeMap:

    for(int i=0;i<=100;i++)
    	{
    		n.number=random.nextInt(100); //add a random number to the node
    		n.visited = false;//set to false inside node
    		tree.put(n, i);//place node into tree
    		n=new node(); //create new node
    	}

    I seen that when I was reading through the errors. However I do not know how to compare them.

  4. #4
    Super Moderator Norm's Avatar
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    Default Re: TreeMap:

    I do not know how to compare them.
    You don't compare them. The TreeMap class code does that.

    Did you read the API doc for the TreeMap class?
    If you don't understand my answer, don't ignore it, ask a question.

  5. #5
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    Default Re: TreeMap:

    Yes... but the tone of your comment makes me think I should do it again. I read it with the preconceived notion that I had to do the comparing.

  6. #6
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    Default Re: TreeMap:

    Quote Originally Posted by jocdrew21 View Post
    I read it with the preconceived notion that I had to do the comparing.
    You must define how each 'node' object is compared to another - the TreeMap then uses this definition to maintain order. See post #2:

    Quote Originally Posted by Norm
    That would mean the class needs to implement Comparable.
    You implement this interface to define how each object should be ordered relative to another.

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