Thread: Need help with programming a simple password checker.

Since you kinda know where to begin... Do that. Your best bet when it comes to getting help is to try until your completely baffled and then post what you've got. From there someone will help push you in the right direction. Hint: Google java Scanner and java equals method.

okay i updated my post

Assuming the password is the same for "all users", you need to establish what that password is in a variable. Then do the same thing you did for username. Then compare them. You will also need a loop to cycle through password entry/check twice.

I wouldn't use ints unless that's what the assignment calls for. You will have to do some extra code for that.

i am very new at this haha youre going to have to go over this with me..i mainly am using ints because that is what we have learned so far haha

Are you familiar with a String?

Keeping it the way it is... You still need to do what I recommended in post #4. You need an int variable to hold the correct password for starters.

How do I go from typing in the username to then typing in the password because every time i type in the username it gives me an error

Hello Ada! I was wondering if you could type out a simple draft of what you are trying to tell me haha I'm sorry but i'm a huge noob at this and i do better with seeing

package class1;
import java.util.Scanner;
//I had to use scanner in this program because i had to create objects that were in the Scanner class, such as in row 17.
// The password to this program is anything with 5 or less letters. Numbers are not allowed.
/**
* @author Spec *
* @version 1.0001, 30 August 2014 *
* This program confirms a password typed into a *
* console window *
*/

public class class1
{
public static void main(String[] args)
{
System.out.println("Password Checker");
Scanner keyboard = new Scanner(System.in);
//This is why I needed Scanner
System.out.println("please enter a username:");
String username = keyboard.next();
//I used String because I needed to use a string of characters and not just one integer like int would be good for.

System.out.print("Please enter a Password: ");
String password = keyboard.next();
// I also had to use if else statements to make the computer decide whether or not what the user put in was right or wrong.
if (isValid(password))
{
System.out.println("You are approved by access control!");
}
else
{
System.out.println("Try again:");
password = keyboard.next();
// I basically remade the code up above except if the person gets it wrong, then the program is terminated.
if (isValid(password))
{
System.out.println("You are approved by access control!");
}
else
{
System.out.println("Sorry");
}
}
}

this is what i have so far! any help with the rest?

--- Update ---

help!

would i just store the correct password by using String password1 = "password";

--- Update ---

I created it so that i can now any 1 character and the password is right but i dont know how to make it a specific password

--- Update ---

package Homework1;
import java.util.Scanner;
//I had to use scanner in this program because i had to create objects that were in the Scanner class, such as in row 17.
// The password to this program is anything with 5 or less letters. Numbers are not allowed.
/**
* @author Spec *
* @version 1.0001, 30 August 2014 *
* This program confirms a password typed into a *
* console window *
*/

public class Homework1
{
public static void main(String[] args)
{
System.out.println("Password Checker");
Scanner keyboard = new Scanner(System.in);
//This is why I needed Scanner
System.out.println("please enter a username:");
String username = keyboard.next();
//I used String because I needed to use a string of characters and not just one integer like int would be good for.

System.out.print("Please enter a Password: ");
String password = keyboard.next();
// I also had to use if else statements to make the computer decide whether or not what the user put in was right or wrong.
if (isValid(password))
{
System.out.println("You are approved by access control!");
}
else
{
System.out.println("Try again:");
password = keyboard.next();
// I basically remade the code up above except if the person gets it wrong, then the program is terminated.
if (isValid(password))
{
System.out.println("You are approved by access control!");
}
else
{
System.out.println("Sorry");
}
}
}


public static boolean isValid(String password) {
// If the user enters any character on the keyboard, then the password will be correct.
//I had to make the password length shorter than how many digits were allowed or else the program wouldn't run. It may have been more code than necessary but it worked out well.

if (password.length() > 1) {
return false;
} else {
char c;
int count = 1;
for (int i = 0; i < password.length() - 1; i++) {
c = password.charAt(i);
if (!Character.isLetter(c)) {
return false;
} else if (Character.isDigit(c)) {
count++;
if (count < 1) {
return false;
}
}
}
}
return true;
}
}



this is my code now but the password will be right for any password that is one character long...how can I make it so it is one single internal password instead of many 1 charcter long passwords....do i even need the public static boolean or can I do it an easier way?

--- Update ---

Thank you so much by the way You're really helping me a lot!

So are you saying I should just get rid of the public static boolean stuff?

--- Update ---

I am so confused now

what do you mean loop fashion? I am very very new at this (like a week into class) so we haven't gone over all of this yet. I am trying to understand but damn am I confused haha

--- Update ---

Gah this sucks...I am just working in circles here haha I havent gotten like anything done in 2 days of trying.

Post your latest code - correctly, in code or highlight tags as explained here, and then update your question. Reviewing the above, I'm not sure what you're working on and what you need help with.

For the second try, the value of 'temp' doesn't change. The line:

keyboard.next();

throws away the user's input rather than save it in temp.

actually I think I may have fixed it! can anyone check to see if this works for them?

package Homework1;
import java.util.Scanner; 
//I had to use scanner in this program because i had to create objects that were in the Scanner class, such as in row 16.
// The password is Tradd.
/**
* @author Spec *
* @version 1.0001, 30 August 2014 *
* This program confirms a password typed into a *
* console window *
*/
 
public class hhh 
{ 
	public static void main(String[] args) {
		//Needs to add a scanner to the program to continue on
		Scanner keyboard = new Scanner(System.in);
 
		//Initial values are set 
		int tries = 1;
		String password = "Tradd";
 
		//print statements that display the programs name 
		System.out.println("Password Checker");
		//Ask user to input username 
		System.out.println("Please enter a Username:");
 
		//takes username from keyboard input
		String username = keyboard.next(); 
		//ask the user to input a secret password
		System.out.println("Please enter your password:"); 
		String temp1 = keyboard.next();
 
		if(temp1.equals(password)) 
		{
		System.out.println("You are approved by access control!"); 
		System.exit(0);
		}
		else
		{
			System.out.println("Try Again:");		
			}
 
		String temp2 = keyboard.next();
 
		if (temp2.equals(password))
		{
			System.out.println("You are approved by access control!");
		}
		else
		{
			System.out.println("Sorry");
		}
		System.exit(0);
	}
}

I added another temp and it ended up working out. Does this work better?