Thread: Unexpected output java

I am trying to write a program for converting positive binary inputs into hex. in the hex output the point (".")is missing.

Suppose my expected output is e7.6 , but i am getting e76.

only the "." is missing.

here is my BinToHex class..

import java.io.*;
 
 
public class BinToHex {
    double tempDec,fractionpart;
    long longofintpart,templongDec;
    String inpu ="11100111.011";
    String hexOutput=null,tempDecString,hex = null;
 
    static int i = 1;
 
    public void convertbintohex() {
 
            if (inpu.contains(".")) {
                int placesAfterPoint = inpu.length() - inpu.indexOf(".") - 1;//every thing
                long numerator = Long.parseLong(inpu.replace(".", ""), 2);//goes 
                double decimalOfInput = ((double) numerator) / (1L << placesAfterPoint);//alright  till here 
 
 
                while (true) {
                    tempDec = decimalOfInput * 16;
                    if (tempDec == (int)tempDec) {
                        tempDecString = String.valueOf((long)tempDec);
                        templongDec = Long.parseLong(tempDecString, 10);
                        hexOutput = Long.toHexString(templongDec);
 
                        break;
                    } else {
                        longofintpart  = (long)tempDec;
                        hex=Long.toHexString(longofintpart);
                        if(i==1){
                            hexOutput = hex + ".";
                            i=i+1;
                        }else{
                            hexOutput = hexOutput + hex;
                        }
                        fractionpart = tempDec-(int)tempDec;
                        decimalOfInput = fractionpart;
                    }
                }
            } else {
                    // this part is ok
                tempDecString = String.valueOf(Integer.parseInt(inpu, 2));
                templongDec = Long.parseLong(tempDecString, 10);
                hexOutput = Long.toHexString(templongDec);
            }
            System.out.println(hexOutput);
    }   
}

my main Test class..

public class Test{
    public static void main(String args[]){
        BinToHex i = new BinToHex();
        i.convertbintohex();    
    }
}

here is how decimal fraction is converted into hex
or here too
plz help me.

what is a "." doing in a hex number? I've never seen that.

Originally Posted by Norm

what is a "." doing in a hex number? I've never seen that.

if there can't be "." in hex then how is a fraction represent in hex. indeed i've seen "." in hex several times.

fraction can be presented in hex

I've never seen any non-decimal number with a point.
I guess its allowed.

What is the algorithm for creating the digits to the right of the point?

Can you show the math needed to do the conversion?
Also provide an example.

What are the steps your program is doing to solve the problem.
For the digits to the left of the point it would do something like this:
convert base 2 digits to int
convert int to base 16 digits

What would it do for the digits to the right of the point?