Thread: I want the java coding to print following # pattern in cmd.exe . So pls help me .. It must start with 6 #'s and end with 2 #'s .

We've established what the goal is, that's good. Now it's time for you to tell us how far you've gotten with it and perhaps you want to ask a question about a specific part you're currently stuck on?

Does that do what you need?

Also, it's advisable to use code tags around your code to make it easier to read. For example, here's your code again with code tags.

public class pattern {
  public static void main(String[] args) {
 
    for (int row = 6; row >= 2; ++row){
      for (int col = 1; col <= row; --col){
        System.out.print("#");
      }
      System.out.println();
    }
  }
}

It looks a lot better right?

Now, does that code do what you need it to? What's the output of it?

shows unending #'s.

You need to work out the logic first.
How many lines need to be printed?
What logic is needed to stop printing #s after the required number are printed for the current line?
How many #s are printed on each line?
How does that compare to the number printed on the previous line?

Sorry, we don't provide code.
You need first to work out the logic.
Consider these points:
how many lines need to be printed? Use a loop for the required number of lines.
the loop control variable normally increases, but it can also decrease. Going from 0 to 5 and from 5 to 0 gives that same number of loop iterations.

Next how many #s are to be printed on the first line?
Then how many on the second line? Hint: one fewer. fewer implies subtracting from a counter

Your code looks close. Make sure the loop variables are changing value in the right direction: increasing or decreasing as is required.