parity

**noura** · October 6th, 2017, 04:49 AM

A bit string has odd parity if the number of 1's is odd. A bit string has even parity if the number of 1's is even. Zero is considered to be an even number, so a bit string with no 1's has even parity. Note that the number of 0's does not affect the parity of a bit string.
Input File: parity.in The input consists of one or more strings, each on a line by itself, followed by a line containing only "#" that signals the end of the input. Each string contains 1–31 bits followed by either a lowercase letter 'e' or a lowercase letter 'o'.
Output: Each line of output must look just like the corresponding line of input, except that the letter at the end is replaced by the correct bit so that the entire bit string has even parity (if the letter was 'e') or odd parity (if the letter was 'o').
Sample Input Sample Output
101e 1010
010010o 0100101
1e 11
000e 0000
110100101o 1101001010
#

* i try to solve it but its dosent work*

**noura** · October 6th, 2017, 04:57 AM

t just start in this way this is right??
how can i complete1Capture.jpg

**John Joe** · October 6th, 2017, 10:26 AM

Please don't post your code as image.The image is too small.

**noura** · October 6th, 2017, 10:51 AM

[/COLOR]how can i do it I am new here

**John Joe** · October 6th, 2017, 11:01 AM

Just post the code here

Example

public class Test{
     public static void main(String[] args)
    {
          // your code
    }
}

Use [CODE] tags to wrap your code.

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