Thread: Help the newbie

package com.company;

public class Main {

public static void main(String[] args) {

double a = (1/84);
double b = Math.sqrt(123456879);
double c = Math.cbrt(2);
double d = Math.PI(Math.sqrt(7));

System.out.printf("%5.6f%n", a);
System.out.printf("%5.6f%n", b);
System.out.printf("%5.6f", c);

}
}

Hey guys, the code above is for few questions i am solving, i am still a newbie at this and would like some help!

Question 1: For "double a = 1/84" should be giving me an actual value but all i am getting is 0.000000, any thoughts ?

Question 2: The square root of 123456789 is 11111.1110606 but in the java program it says 11111.115111, anyway to get a more accurate result ?

Question 3: I need to calculate PI to the power of 7 so i tried Math.PI(Math.sqrt(7)); but it's giving me an error saying "Method call expected" But when i add the multiplication sign between mathPI and mathSQRT "Math.PI*(Math.sqrt(7));" it gives me a different answer than what i wanted.

Thank you guys ^^

Please copy the full text of the error message and paste it here. It has important info about the error.

It just says Method call expected with this error

Error10, 24) java: cannot find symbol
symbol: method PI(double)
location: class java.lang.Math

Please explain. Post the output to show what you are talking about and show what you want.

PI to the power of 7 should give me 3020.29322778 but i am getting 8.311873

Sorry for the late reply!

Please post the code that gives that result.

double d = Math.PI*(Math.sqrt(7));
System.out.printf("%5.6f", d);

P.S if i removed the multiplication sign and used "double d = Math.PI(Math.sqrt(7));" i'll be getting that error i showed you.