Thread: Exercise 5.1 in (intro to javaprogramming 10th edition)

/*
    (Count positive and negative numbers and compute the average of numbers) Write
    a program that reads an unspecified number of integers, determines how many
    positive and negative values have been read, and computes the total and average of
    the input values (not counting zeros). Your program ends with the input 0. Display
    the average as a floating-point number. Here is a sample run:
 
      Enter an integer, the input ends if it is 0: 1 2 -1 3 0
      The number of positives is 3
      The number of negatives is 1
      The total is 5.0
      The average is 1.25
*/
 
//So this was my answer but when the program starts running, the compiler freezes.
//Tried using intelliJ, same result but allowed me to enter numbers without going any further.
 
import java.util.*;
 
public class testing7 {
  public static void main(String[] args) {
 
    Scanner input = new Scanner(System.in);
 
    System.out.println("Enter an integer (The input ends if it is 0): ");
    int integer = input.nextInt();
 
    int count = 0;
    int negativeCount = 0;
    int positiveCount = 0;
    double total = 0;
 
    while(integer != 0) {
        if(integer < 0)
          negativeCount++;
         else
          positiveCount++;
 
     total += integer;
     count++;
    }
 
    System.out.println("The number of positives is: " + positiveCount);
    System.out.println("The number of negatives is: " + negativeCount);
    System.out.println("The total is: " + total);
 
    double average = total / count;
 
    System.out.println("The average is:  " +  average);
 
  }
}

Hints only if possible please :

What do you think this loop is doing? Go thru it carefully by hand.

while(integer != 0) {
        if(integer < 0)
          negativeCount++;
         else
          positiveCount++;
 
     total += integer;
     count++;
}

Regards,
Jim