Thread: Help PLZ .. =(

Hi All ..

I need help with this Program .. The question is :

Use a one-dimensional array to solve the following problem:Write an application that inputs five numbers, each of which is between 10 and 100, inclusive. As each number is read, display it only if it is not a duplicate of a number already read. Provide for the “worst case,” in which all five numbers are different. Use the smallest possible array to solve this problem. Display the complete set of unique values input after the user inputs each new value.

and this is the code I wrote :

First Class containing main :

public class UniqueTest
{
   public static void main( String[] args )
     {
       Unique obj = new Unique();
       obj.getNumbers();
     } 
}

Second Class :

import java.util.Scanner;
 
public class Unique
 {
 
     public void getNumbers()
     {
        Scanner input = new Scanner( System.in );
        int [] array = new int [5];
 
        int count = 0; // number of uniques read
        int entered = 0; // number of entered numbers
        int num =0;
 
       while( entered < array.length )
        {
           System.out.print( "Enter number: " );
            num = input.nextInt(); 
 
            if ((num>=10) && ( num<=100))
             {
                boolean containsNumber = false;
                entered++;
 
                 for (int i=0;i<array.length;i++)
                   {
         	 if (array[i]==num)
         	   containsNumber=true;
                   }
 
                 if ( !containsNumber )
                  { 
                     for (int i=0; i<array.length;i++)
                       {
                          array[i]=num;
                          count++;
                       }
 
                   } // end if
 
                 else
                  System.out.printf( "%d has already been entered\n",num );
               } // end if
 
                else
          System.out.println( "number must be between 10 and 100" );
 
         //Print the contents of the Array :
          for(int i=0 ; i<array.length;i++)
           {
            System.out.printf("%d\n",array[i]);
             break;
           }
 
       } // end while
    } // end method getNumbers
 } // end class Unique

The problem is that when I enter new unique number after the first number ,it will remove the first number and print only the second number .. This is the OutPut :

Enter number: 11
11
Enter number: 27
27
Enter number: 80
80
Enter number: 100
100
Enter number: 60
60

and I want the OutPut to be like this :

Enter number: 11
11
Enter number: 27
11  27
Enter number: 80
11  27  80
Enter number: 100
11 27  80  100
Enter number: 60
11  27  80  100 60

Any Help is Greatly appreciated ..

Hi JavaPF..

THX ALOT .. I really appreciate your help ..

I run the program .. but I faced another Problem :

The Code after modification :

import java.util.Scanner;
 
public class Unique {
 
public void getNumbers() {
  Scanner input = new Scanner(System.in);
	int[] array = new int[5];
 
	int count = 0; // number of uniques read
	int entered = 0; // number of entered numbers
	int num = 0;
 
	while (entered < array.length) 
		{
		System.out.println("Enter number: ");
		num = input.nextInt();
 
		if ((num >= 10) && (num <= 100)) {
			boolean containsNumber = false;
			entered++;
 
			for (int i = 0; i < array.length; i++) 
			 {   if (array[i] == num)		
			     containsNumber = true;
			 }	
 
			if (!containsNumber) {
 
			array[count] = num;
 
			count++;
 
			} // end if
 
			else
 
			System.out.printf("%d has already been entered\n", num);
 
	     	      } // end if
 
		  else
		   System.out.println("number must be between 10 and 100");
 
		// Print the contents of the Array :
		for (int i =0;  i< entered; i++) {
 
		System.out.print(array[i] + " ");
		}
 
                                  System.out.println();
	} // end while
            } // end method getNumbers
} // end class Unique

The OutPut is :

Enter number: 
30
30 
Enter number: 
40
30 40 
Enter number: 
30
30 has already been entered
30 40 0 
Enter number: 
50
30 40 50 0 
Enter number: 
20
30 40 50 20 0

The Problem is value (0) .. How can I prevent it .. ??

The OutPut Should be :

Enter number: 
30
30 
Enter number: 
40
30 40 
Enter number: 
30
30 has already been entered
30 40  
Enter number: 
50
30 40 50  
Enter number: 
20
30 40 50 20

Please tell me if you know the answer ..

I think it'd be easier for you to add the numbers to string

String thing += num + " "

and then parse it

int ln = 0;
for(int i=0;i<thing.length()) {
 if(this.substring(i,i) == " ") {
  System.out.printIn(this.substring(ln,i-1)
  ln = i+1;
 }
}

. But that's just my opinion. Everybody has their own.

EDIT: Oops. Sorry. You had to do it an Array.

I'm a newbie but I think I figured it out:

public class DuplicateEliminator {
 
   public void getNums(){
        Scanner input=new Scanner(System.in);
	int[]digits=new int[4];
        int count=0;
	int entered=0;
	int num;
 
        while (entered<digits.length) {
            System.out.print("Enter a number between 10 and 100: \n");
	    num = input.nextInt();
		if ((num>=10)&&(num<=100)) {
                    boolean isDup=false;
                    entered++;
 
                    for (int i=0;i<digits.length;i++) {
                            if (digits[i]==num)
			     isDup=true;
                             entered--;//do not add duplicate digits to array
                             }
 
                            if (!isDup) {
                                digits[count]=num;
			        count++;
                              	}
               else
                    System.out.printf("%d is a duplicate number\n", num);
 
               for(int i=0;i<count;i++) {
                    System.out.printf(digits[i] + " ");
                    }
	}
      }
    }
 }