Thread: Fetch string in JAVA

Hello,

I would like to check a string contains "hello" or not?

In the following string if we remove some characters we have "hello".

ahhellllloou

sdfhwesflrfgvloouhhlh

But the following string is not matched with "hello".

hlelo


I wrote a program and it works fine but Do we have a simple way? for example with regex?

Thanks

package newpackage;
 
import java.util.*; 
 
public class NewMain 
{
 
    public static void main(String[] args)
    {
        Scanner input = new Scanner(System.in);
 
        String myString = input.next().toLowerCase();
        char[] myChar = new char[myString.length()]; 
        char[] finalChar = new char[5];
        int j = 0;
        for (int i = 0; i < myString.length(); i++) 
        {
            if ((myString.charAt(i) == 'h') ||
                    (myString.charAt(i) == 'e') ||
                    (myString.charAt(i) == 'l')
                    || (myString.charAt(i) == 'o'))
                myChar[j++] = myString.charAt(i);
        }
        int countH =0, countE = 0, countL = 0, countO = 0;
        int FcountH =1, FcountE = 1, FcountL = 2, FcountO = 1;
 
        for (int i = 0; i < myChar.length; i++) 
        {
            if (myChar[i] == 'h')
                countH++;
          else  if (myChar[i] == 'e')
                countE++;
          else  if (myChar[i] == 'l')
                countL++;
          else  if (myChar[i] == 'o')
                countO++;
        }
        j = 0;
         for (int i = 0; i < myChar.length; i++) 
        {
              if (myChar[i] == 'h')
              {
                  if (countH > 1 && FcountH == 1){
                      finalChar[j++] = 'h';
                      countH--;
                      FcountH = 0;
                  }
                  else if (countH == 1 && FcountH == 1)
                  {
                       finalChar[j++] = 'h';
                       FcountH = 0; 
                  }
 
              }
              else if (myChar[i] == 'e' && FcountE == 1)
              {
                  if (countE > 1){
                     finalChar[j++] = 'e';
                      countE--;
                      FcountE = 0;
                  }
                  else if (countE == 1 && FcountE == 1){
                        finalChar[j++] = 'e';
                          FcountE = 0;
                                  }
              }
             else if (myChar[i] == 'l' )
              {
                  if (countL > 2 && FcountL >= 1){
                         finalChar[j++] = 'l';
                      countL--;
                      FcountL--;
                  }
                   else if (countL >=1 &&  FcountL != 0){
                        finalChar[j++] = 'l';
                         countL--;
                      FcountL--;
                   }
              }
             else if (myChar[i] == 'o' &&  FcountO == 1)
              {
                  if (countO > 1){
                       finalChar[j++] = 'o';
                      countO--;
                      FcountO = 0;
                  }
                  else if (countO == 1 &&  FcountO == 1){
                        finalChar[j++] = 'o';
                         FcountO = 0;
                   }
              }
        }
        String finalString = new String(finalChar);
        if (finalString.equals("hello"))
                    System.out.println("YES");
                    else
                    System.out.println("NO");
    }
}

Originally Posted by Norm

What is the logic for doing the checking?

Thank you, sorry my English language is bad.

I did not get you.

I am learning JAVA language.