Thread: Check String Pattern in Java

Hello,

First I get a number (numbers of string to check) then get the pattern.
If the string contains the pattern, print Yes otherwise No.

For example:
4 quera102

quEra0012
qu0erraa12
sN0Ap12
qurra00L

No
Yes
No
No


I wrote the below code but I get 71 from 100.

package My;
import java.util.*;
 
public class NewMain
{
 
    public static void main(String[] args) 
    {
        Scanner scanner = new Scanner(System.in);
 
        int n = scanner.nextInt();
 
        String pattern = scanner.next();
 
        String []myString = new String[n];
 
        for (int i = 0; i< n ; i++)
        {
            myString[i] = scanner.next();
        }
        boolean flag = true;
           for (int i = 0; i< n ; i++)
        {
            flag = true;
            for (int j = 0 ; j < myString[i].length(); j++)
            {
                int indexOf = pattern.indexOf(myString[i].charAt(j));
                if (indexOf == -1)
                {
                    flag = false;
                    break;
                }
            }
            if (flag == false)
                {
                   System.out.println("No");
                }
                    else
                {
           System.out.println("Yes");
 
                }
        }
 
    }
}

Originally Posted by Norm

Does that mean the code misses 29 items?
Can you print the 29 items that the code misses that should have been detected so we can see where it has the problem?

My point is 71% from 100%

We don't have failed examples.

I attached the output and two conditions in question.

https://i.ibb.co/9gmvHv8/Screenshot-...-07-155804.jpg

https://i.ibb.co/WPMB4mw/Screenshot-...-07-155517.jpg