Thread: Im beginner need a solution for one logic

Find the largest sum of an individual digit of an element in array
Ex a=[23,34,56,47,88,12,]
2+3=5
3+4=7
Same way largest sum is 16
The output should be 88

I would suggest creating 2 arrays, one to store those integers you've listed and one to store the combined values of the digits. To get the values of the combined digits you can use a while loop.

 
 
while(i<5) {
 
    combined[i]= (digit[i] % 10 ) + (digit[i]/10);
	i++;
    }

--- Update ---

Hey, norm I'm a little new to java as well what do you think of the solution and how would you approach this problem.

The values you've given are/can be stored in an array. The code for the loop I provided above does as such: the loop will run as long as

 i < 5

the line

 combined[i]= (digit[i] % 10 ) + (digit[i]/10);

is what adds the digits of the numbers you originally stored in your first array. For this problem you are working with two arrays, "combined" and "digit". "Digit" holds the integers you've listed while "combined" hold the addition of the digits of the numbers. A trick to isolate the digits of a base-10 number is to use "%" and "/". Both operands are divisor, but the "/" gives the whole value of the division ex. 25 / 10 = 2.5, but java will out put only "2", whereas if you do 25%10 it will out put the remainder ie. "5". This line uses that logic to to isolate the digits. Once isolated they are combined and stored in a second array the

 [i]

is a place holder in the array and is incremented by one each time the loop is excecuted.