Thread: Help me to figure out how code working

Hello everyone. Please tell me how working function

number = scanner.nextInt();
        if ((number & 0) == 1)`

Full code

package com.company;
 
import java.util.Scanner;
 
public class CheckParity {
    public static void main(String[] args) {
        int number;
        Scanner scanner = new Scanner(System.in);
        System.out.println("Enter number: ");
        number = scanner.nextInt();
        if ((number & 0) == 1) {
            System.out.println("Even number");
        } else {
            System.out.println("The number is not even");
        }
    }
}

--- Update ---

The most of I can't understand if ((number & 0) == 1)

Why we using number and &?

& its and. So why we do that?

Why we comparing number and 0? And why after priority () we use == 1?

Originally Posted by Jexly

Why we using number and &?

i don't think this code is correct. And regardless, using bitwise operators (&, | etc. ) only really makes sense if you are actually interested in individual bits.
Seems like the assignment here is to find out if a number is odd or even. So the proper test would be

if ( number % 2 == 0 )
{
     even
}
else
{
     odd
}

Certainly! Let's break down the code:

```java
number = scanner.nextInt();
if ((number & 0) == 1)
```

1. `number = scanner.nextInt();`: This line reads an integer input from the user using the Scanner class and assigns it to the variable 'number'.

2. `if ((number & 0) == 1)`: This line checks if the bitwise AND operation between 'number' and '0' equals 1.

- The `&` operator performs a bitwise AND operation, meaning it compares each bit of the operands and returns 1 only if both bits are 1.

- In this case, 'number' is compared with '0', which results in 0 for any integer since bitwise AND with 0 results in 0.

- So, effectively, `(number & 0)` always equals 0, regardless of the value of 'number'.

- Consequently, the condition `(number & 0) == 1` is always false, because `(number & 0)` is always 0, and 0 is not equal to 1.

In essence, the condition if ((number & 0) == 1) will always result in the "The number is not even" message being printed, regardless of the value of 'number'. Therefore, it seems there might be a misunderstanding or an error in the logic of the code. If you're seeking help with Java assignment or need help understanding bitwise operations and logical conditions better, there are various online resources and communities where you can find support and guidance, such as ProgrammingHomeworkHelp.com.