Thread: Min Number from array

package com.company;
 
public class ArrayMinMaxEachString {
    public static void main(String[] args) {
        int[][] array = {
                {1, 2, 3, 4, 5, 6, 7, 8, 9},
                {11, 12, 13, 14, 15, 16, 17, 18, 19}
        };
 
        for (int i = 0; i < array.length; i++) {
            for (int j = 0; j < array[0].length; j++) {
                System.out.print(array[i][j] + " ");
            }
            System.out.println();
        }
 
        //min
        int min = array[0][1];
        for (int k = 0; k < array.length; k++) {
            if (min > k) {
                min = k;
 
            }
        }
        System.out.println("\n\nMin is: " + min);
    }
}

Can you please explain what exactly am I doing wrong? Why doesn't it show the minimum number?

--- Update ---

My assignment looks like this, in case it helps anyone:

Create a two-dimensional 5x8 array of type int and initialize it with an initialization block.
Find the maximum and minimum value in each "line" and write these values into a 5x2 two-dimensional array.
Print both arrays.

Problem #1 is you have not defined a 5x8 array.
You have defined a 2x9 array [0 to 1][0 to 8].
Each bracketed set of numbers is one 'row' of the matrix.

        int[][] array = {
                {1, 2, 3, 4, 5, 6, 7, 8},
                {11, 12, 13, 14, 15, 16, 17, 18},
                {111, 112, 113, 114, 115, 116, 117, 118},
                {211, 212, 213, 214, 215, 216, 217, 218},
                {311, 312, 313, 314, 315, 316, 317, 318}
        };

Next problem is that you are initializing min with the SECOND value not the first. Why are you skipping [0][0]?
The biggest problem however is that you are only looping the single dimension of the array. You need to nest two for loops and process every element of the array. Two dimensions means two for next loops nested.