Why my String does not appear ?

**siid14** · March 10th, 2022, 09:02 PM

Instruction: 73. Write a Java program to create a new string taking first and last characters from two given strings. If the length of either string is 0 use "#" for missing character.
Test Data: str1 = "Python"
str2 = " "
Sample Output:
P#

Link of PB : https://www.w3resource.com/java-exer...asic/index.php

Here is my program for this pb :

try (Scanner input = new Scanner(System.in)) {
            // get user String input
            System.out.print("Input Str1 : ");
            String Str1 = input.next();
            System.out.print("Input Str2 : ");
            String Str2 = input.next();
 
            // check String Str1 & Str2 length for diff case
            if (Str1.length() != 0 && Str2.length() != 0) { // case a
                System.out.println(Str1.substring(0, 1) + Str2.substring(Str2.length() - 1, Str2.length()));
            } else if (Str1.length() != 0 && Str2.length() == 0) { // case b
                System.out.println(Str1.charAt(0) + "#");
            } else
                System.out.println("#" + Str2.substring(Str2.length() - 1, Str2.length())); // case c
        }

The issue is that when I test Case b & c it does return me for example P" (case b) or "P (case c). Why it is not P# or #P as I am expecting with for input Python and ""
By the way, Case a works with no issue.

**Norm** · March 10th, 2022, 09:35 PM

Please copy the program's actual output and paste it here. Add comments to point out what was unexpected.

Please edit your post and wrap your code with code tags:

[code]
**YOUR CODE GOES HERE**
[/code]

to get highlighting and preserve formatting.

**BosnianKingdom** · March 10th, 2022, 11:50 PM

The name of your variables should be lower case, just fyi. I would use the nextLine method of the Scanner class. Instead of complicating things by dealing with the 2 strings at the same time, I would divide it into 2 separate sections like this:

try (Scanner input = new Scanner(System.in)) {
	// get user String input
	System.out.print("Input Str1 : ");
	String str1 = input.nextLine();
	System.out.print("Input Str2 : ");
	String str2 = input.nextLine();
	String result;
 
	if(str1.length() == 0){
		result = "#";
	}
	else{
		result = String.valueOf(str1.charAt(0));
	}
 
	if(str2.length() == 0){
		result += "#";
	}
	else{
		result += String.valueOf(str2.charAt(str2.length()-1));
	}
 
	System.out.println(result);
}

**siid14** · March 11th, 2022, 03:52 AM

I saw your code @BosnianKingdom, it's pretty quick and easy to deal with. Thank you, it would give me another way to handle it. But still, I'm trying to understand why the "#" does not appear in my output. Did something wrong with my code? Here is the output I got :

Input Str1 : ""
Input Str2 : ateyaba
"a

--- Update ---

Also, @BosnianKingdom, why did you use String.valueOf? I think it is unnecessary. Your code works well with the followings (below) :

result += str1.charAt(0);
result += str2.charAt(str2.length()-1);

After trying your code, here is my output :

Input Str1 : ateyaba
Input Str2 : "
a"

I think the issue should come from the compiler.. ? Maybe?

**Norm** · March 11th, 2022, 07:13 AM

why the "#" does not appear

What conditions need to be true for that?
Are those conditions met with your input?

**siid14** · March 24th, 2022, 05:35 PM

Here you have a full details about the condition to be meet :

Instruction: 73. Write a Java program to create a new string taking first and last characters from two given strings. If the length of either string is 0 use "#" for missing character.
Test Data: str1 = "Python"
str2 = " "
Sample Output:
P#

**Norm** · March 24th, 2022, 05:57 PM

Sorry, I was asking about the conditions that are coded in your program.

Print out the lengths of the two Strings to see what is being tested.

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