I dont get it....please help

**DestinyChick1225** · June 24th, 2010, 12:09 AM

I really dont understand why:

First, my program is loading every number possible before prompting my user for a number between boundaries.

Second, why my program keeps listing off way more numbers then needed.

PLEASE HELP! IM SO CONFUSED! Here is my code:

import java.util.Scanner;
 
public class user_Program
{
    private boolean primes[] = new boolean [50001];
 
    private int upper = 50000;
 
    private int lower = 1;
 
    public void processSieve()
    {
        primes[0] = false;
        primes[1] = false;
        for (int a = 2; a < 50000; a++)
        {
            primes[a] = true;
        }
 
        for (int a = 2; a <= 223; a++)
        {
            if (primes[a])
            {
                              for (int b = a; b <= 223; b++)
                {
                    int c = (a * b);
                    primes[c] = false;
                }
            }
        }
    }
 
    public void getBoundaries()
    {
        System.out.println ("Please enter a lower boundary and an upper boundary and I will print sexy prime pairs between those boundaries.");
 
        Scanner i = new Scanner (System.in);
 
        System.out.print("Please enter the lower boundary (between 1 and 50000): ");
        lower = i.nextInt();
        while ((lower <= 0) || (lower > 50000))
        {
            System.out.print("Please enter the lower boundary (between 1 and 50000): ");
                                              lower = i.nextInt();
        }
 
        System.out.print("Please enter the upper boundary (between 1 and 50000): ");
        upper = i.nextInt();
        while ((upper <= 0) || (upper > 50000))
        {
            System.out.print("Please enter the upper boundary (between 1 and 50000): ");
            upper = i.nextInt();
        }
 
        while (lower > upper)
        {
            System.out.println ("Your upper boundary cannot be smaller than your lower boundary.");
 
            System.out.print("Please enter the lower boundary (between 1 and 50000): ");
            lower = i.nextInt();
            while ((lower <= 0) || (lower > 50000))
            {
                                 System.out.print("Please enter the lower boundary (between 1 and 50000): ");
                lower = i.nextInt();
            }
 
            System.out.print("Please enter the upper boundary (between 1 and 50000): ");
            upper = i.nextInt();
            while ((upper <= 0) || (upper > 50000))
            {
                System.out.print("Please enter the upper boundary (between 1 and 50000): ");
                upper = i.nextInt();
            }
 
        }
 
    }
 
    public void showPrimes()
    {
        System.out.printf("Here are all of the sexy prime pairs in the range %d to %d, one pair per line:\n", lower, upper);
 
        int counter = 0;
        for (int a = lower; a <= upper; a++)
        {
    if (primes[a] == true)
            {
                int b = (a + 6);
                if (b <= 50000)
                {
                    if (primes[b] == true)
                    {
                        System.out.printf("%d and %d\n", a, b);
                        counter++;
                    }
                }
            }
        }
 
        System.out.printf("There were %d sexy prime pairs displayed between %d and %d\n", counter, lower, upper);
    }
}

**Faz** · June 24th, 2010, 07:37 AM

Could you give us more detail say give a sample of what you expect to happen for example what you expect the output to be if you set the boundries to 2 and 50 and what output you actually get. Also you might want to explain what prime pairs are I know but alot of people wouldn't(I know google is there but they are taking their time to help you already)

**DestinyChick1225** · June 28th, 2010, 06:12 PM

A sample of what i am suppose to get:

Please enter a lower boundary and an upper boundary and I will print all of the
sexy prime pairs between those boundaries.
Please enter the lower boundary (between 1 and 50000): 0
Please enter the lower boundary (between 1 and 50000): 50001
Please enter the lower boundary (between 1 and 50000): 150
Please enter the upper boundary (between 1 and 50000): 0
Please enter the upper boundary (between 1 and 50000): 50001
Please enter the upper boundary (between 1 and 50000): 100
Your upper boundary cannot be smaller than your lower boundary
Please enter the lower boundary (between 1 and 50000): 8997
Please enter the upper boundary (between 1 and 50000): 9200
Here are all of the sexy prime pairs in the range 8997 to 9200, one pair per line:
9001 and 9007
9007 and 9013
9043 and 9049
9103 and 9109
9127 and 9133
9151 and 9157
9181 and 9187
There were 7 sexy prime pairs displayed between 8997 and 9200

Defintion of Prime Pairs (from Wikipedia:

In mathematics, a prime number (or a prime) is a natural number greater than one whose only positive divisors are one and itself. A natural number that is greater than one and is not a prime is called a composite number. The numbers zero and one are neither prime nor composite. The property of being a prime is called primality. Since 2 is the only even prime number, the term odd prime refers to all prime numbers greater than 2

In mathematics, a sexy prime is a pair (p, p + 6) of prime numbers that differ by six. The name "sexy prime" stems from the Latin word for six: sex

**Norm** · June 28th, 2010, 08:30 PM

Now could you show us what you do get?

**DestinyChick1225** · June 28th, 2010, 08:41 PM

first before it prompts the user for a lower number it goes through all the primes between 1 and 50000

This is what it reads:

There were 40731 sexy prime pairs displayed between 1 and 50000
Please enter a lower boundary and an upper boundary and I will print sexy prime pairs between those boundaries.
Please enter the lower boundary (between 1 and 50000): 89978997
Please enter the lower boundary (between 1 and 50000): 8997
Please enter the upper boundary (between 1 and 50000): 9200
Here are all of the sexy prime pairs in the range 8997 to 9200, one pair per line:
8997 and 9003
8998 and 9004
8999 and 9005
9001 and 9007
9002 and 9008
9003 and 9009
9005 and 9011
9007 and 9013
9008 and 9014
9009 and 9015
9012 and 9018
9013 and 9019
9015 and 9021
9016 and 9022
9019 and 9025
9023 and 9029
9025 and 9031
9026 and 9032
9029 and 9035
9031 and 9037
9032 and 9038
9033 and 9039
9034 and 9040
9035 and 9041
9036 and 9042
9037 and 9043
9038 and 9044
9040 and 9046
9042 and 9048
9043 and 9049
9044 and 9050
9048 and 9054
9049 and 9055
9050 and 9056
9051 and 9057
9053 and 9059
9054 and 9060
9056 and 9062
9058 and 9064
9059 and 9065
9060 and 9066
9062 and 9068
9064 and 9070
9066 and 9072
9068 and 9074
9069 and 9075
9070 and 9076
9074 and 9080
9075 and 9081
9076 and 9082
9077 and 9083
9081 and 9087
9084 and 9090
9087 and 9093
9090 and 9096
9091 and 9097
9092 and 9098
9093 and 9099
9094 and 9100
9095 and 9101
9097 and 9103
9098 and 9104
9099 and 9105
9100 and 9106
9101 and 9107
9103 and 9109
9104 and 9110
9105 and 9111
9107 and 9113
9108 and 9114
9109 and 9115
9111 and 9117
9113 and 9119
9114 and 9120
9115 and 9121
9117 and 9123
9120 and 9126
9121 and 9127
9122 and 9128
9123 and 9129
9126 and 9132
9127 and 9133
9128 and 9134
9129 and 9135
9131 and 9137
9132 and 9138
9133 and 9139
9134 and 9140
9135 and 9141
9136 and 9142
9138 and 9144
9140 and 9146
9141 and 9147
9142 and 9148
9146 and 9152
9147 and 9153
9148 and 9154
9149 and 9155
9151 and 9157
9152 and 9158
9154 and 9160
9155 and 9161
9156 and 9162
9157 and 9163
9160 and 9166
9162 and 9168
9166 and 9172
9168 and 9174
9170 and 9176
9171 and 9177
9172 and 9178
9174 and 9180
9175 and 9181
9176 and 9182
9177 and 9183
9178 and 9184
9180 and 9186
9181 and 9187
9182 and 9188
9183 and 9189
9184 and 9190
9185 and 9191
9186 and 9192
9187 and 9193
9188 and 9194
9189 and 9195
9190 and 9196
9191 and 9197
9193 and 9199
9194 and 9200
9195 and 9201
9197 and 9203
9199 and 9205
9200 and 9206
There were 134 sexy prime pairs displayed between 8997 and 9200

**Norm** · June 28th, 2010, 08:48 PM

That would indicate that your tests for the "sexy prime pairs" needs work.

It looks like all the numbers in that range pass the test.
What is the test you use to see if a number is prime?

Why is the value 223 in the following statement?
for (int a = 2; a <= 223; a++)

**DestinyChick1225** · June 28th, 2010, 09:38 PM

Test:

public class user_ProgramTest
{
    public static void main ( String args[] )
    {
        user_Program foo = new user_Program();
        foo.processSieve();		// run the Sieve algorithm
        foo.showPrimes();		// shows entire set of sexy pairs, 1419 of them
        foo.getBoundaries();		// get lower and upper boundaries
        foo.showPrimes();		// now shows sexy pairs between lower and upper
    }
}

**Charlie** · June 29th, 2010, 02:09 AM

for (int a = 2; a <= 223; a++)
        {
            if (primes[a])
            {
                              for (int b = a; b <= 223; b++)
                {
                    [B][I]int c = (a * b);[/I][/B]
                    primes[c] = false;
                }
            }
        }

Notice how youre declaring the variables type every time you set it. Try to do that outside this codeblock (int c

and then just do c= (a*b);.

EDIT:

Found the same mistak further down too:

 if (primes[a] == true)
            {
               [B][I] int b = (a + 6);[/I][/B]
                if (b <= 50000)
                {
                    if (primes[b] == true)
                    {
                        System.out.printf("%d and %d\n", a, b);
                        counter++;
                    }
                }
            }

This should be where your code goes wrong, seeing as you have an array full of trues.

**Faz** · June 29th, 2010, 03:09 AM

Originally Posted by Charlie

for (int a = 2; a <= 223; a++)
        {
            if (primes[a])
            {
                              for (int b = a; b <= 223; b++)
                {
                    [B][I]int c = (a * b);[/I][/B]
                    primes[c] = false;
                }
            }
        }

Notice how youre declaring the variables type every time you set it. Try to do that outside this codeblock (int c

and then just do c= (a*b);.

EDIT:

Found the same mistak further down too:

 if (primes[a] == true)
            {
               [B][I] int b = (a + 6);[/I][/B]
                if (b <= 50000)
                {
                    if (primes[b] == true)
                    {
                        System.out.printf("%d and %d\n", a, b);
                        counter++;
                    }
                }
            }

This should be where your code goes wrong, seeing as you have an array full of trues.

I don't think that would make a difference. Norm is right the logic you are using to check if a number is prime is flawed I just ran a similar logic in VBA in excel to show this.

9000
9006
9009
9010
9016
9017
9018
9020
9021
9024
9025
9027
9028
9030
9035
9039
9040
9042
9044
9045
9047
9048
9050
9052
9060
9061
9062
9063
9064
9065
9071
9072
9073
9075
9078
9085
9086
9088
9089
9090
9095
9100
9102
9106
9108
9112
9114
9116
9118
9120
9125
9126
9128
9129
9130
9135
9143
9144
9145
9150
9152
9153
9154
9156
9159
9163
9164
9165
9167
9168
9169
9170
9174
9176
9177
9179
9180
9184
9185
9191
9196
9198
9200

Those are the only numbers your "sieve" is setting to not be prime in that range. You'll notice 9010 and 9016 (among others) are there which your sieve did catch and they aren't shown in the output.

I see your logic as 223 * 223 is near 50000(theres still quite a few missing out) but your missing a lot of others. say 4447 * 2 or whatever but basically your missing out on a lot of even numbers because you are only going to 446 in eliminating all even numbers(i.e. divisible by 2).

I wrote a handy little PrimeChecker but I doubt I'll get a chance to post it for you any time soon and I think it would be better if you wrote it yourself anyway.

Mine was based on Integer factorization(<---thats a link to wikipedia but a quick google search will probably get better explainations) it can be pretty slow but I think maybe 50000 is low enough to be fast enough.

EDIT: Or you could use a simpler one there are some shorter algorithims you could use that aren't as accurate but might be better to use I think I needed that calculator as I was checking all primes up to 2 million.

**Charlie** · June 29th, 2010, 06:17 AM

Why are we checking 223 multiples btw? If were only trying to avoid the small numbers like 2 etc, why dont we just set them all to true and falsify em if they dont pass a check, starting with 2 iterating to the number itself?

**Faz** · June 29th, 2010, 06:52 AM

Originally Posted by Charlie

Why are we checking 223 multiples btw? If were only trying to avoid the small numbers like 2 etc, why dont we just set them all to true and falsify em if they dont pass a check, starting with 2 iterating to the number itself?

That would be a simple but not foolproof way of doing it. If you went through and set all mulitples of 2, 3,5,7,9,11 and 13 you would get most primes but there would be some missing.(EDIT: sorry I may have misunderstood your post I thought you meant just check for low numbers did you mean check all up to 50,000?)

EDIT However you did remind me of quite a nice way of checking numbers called the Sieve of Eratoshenes check the info here:
Sieve of Eratosthenes - Wikipedia, the free encyclopedia

That should work really well for an array of booleans actually.

This is the part you should be interested in

To find all the prime numbers less than or equal to a given integer n by Eratosthenes' method:

Create a list of consecutive integers from two to n: (2, 3, 4, ..., n). (n being 50000 in your case)
Initially, let p equal 2, the first prime number.
Strike from the list all multiples of p less than or equal to n. (2p, 3p, 4p, etc.)
Find the first number remaining on the list after p (this number is the next prime); replace p with this number.
Repeat steps 3 and 4 until p2 is greater than n.
All the remaining numbers in the list are prime.

Actually check Eulers sieve as well I'm not familiar with that one it's further down the same page.

**Charlie** · June 29th, 2010, 11:56 AM

Aye, that was kind of what I was thinking. Going to 50k is useless tho since a number can never be divided by more than half its value (if we want an answer bigger than, or equal to 2).

Got this idea of how to do this another way I think. How bout this?:

1. set a max number.
2. Create an arraylist to skip those pesky size-issues that normal arrays have.
3.

import java.util.ArrayList;
 
 
/**
 *
 * @author Charlie
 */
public class NewClass {
 
    ArrayList primes = new ArrayList();
 
    public void primes(int maxnum){
 
	for(int i = 3; i < maxnum ;i++){
		primes.add(i); // add it to the arraylist
 
		for(int i2=2; i2 <= (i/2); i2++){
			//If we manage to divide it without getting strange numbers, we remove it from our arraylist
 
                        if(i%i2 == 0){
 
                              primes.remove(primes.size() - 1);
                              break;
 
			}
		}
 
	}
 
    }
 
    public void printPrimes(){
        for(int i = 0; i<primes.size();i++){
            System.out.println(primes.get(i));
        }
    }
 
    public static void main(String[] args){
        System.out.println("Hi, starting to count primes: \n\n");
        NewClass sven = new NewClass();
 
        sven.primes(50000);
        sven.printPrimes();
    }
 
}

4. Profit.

Checking the lists values for "sexy" primes should now be a piece of cake

Ps. First time working with primes, so feel free to rage if I've missunderstood it.

**Faz** · June 30th, 2010, 03:16 AM

Actually you only need to go to the square root of 50,000 so I think 224 (so that's where they 223 came from)

Repeat steps 3 and 4 until p2 is greater than n.

That came out as p2 but it's actually p squared.

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