Thread: difficult program

help me i don't know what

Hi Fordy252,
I can't open your file.
Bye

Please provide more details - error messages, expected and observed output, along with the source code in the post itself (between the [highlight=java][/highlight] tags). And...recommended reading: How To Ask Questions The Smart Way

Your break statements will exit the for loops prematurely.

if (num == distinct[x])

At this point, distinct[x] is emtpy for all indexes in the array.

I can't open your file.........

Originally Posted by javapenguin

Your break statements will exit the for loops prematurely.

if (num == distinct[x])

At this point, distinct[x] is emtpy for all indexes in the array.

It's not empty but 0 and what if one of element is equal to 0 in OP's numbers array?

else
				distinct[disNumCount] = num;//if the number is not there, save it 
				disNumCount++;
				break;

Why do you need to make it nested loop if it will break exactly after one iteration?

distinct array is empty man!

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