Thread: Program to find how many letters start with vowels

The program's output is n't correct

Here's the code......

 
import java.io.*;
class Vowels   
 {
    void Input()throws IOException
         {
             BufferedReader a = new BufferedReader(new InputStreamReader(System.in));
             System.out.println("Enter your Sentence");
             String b = a.readLine();
              int c = b.length();
              int d=0,f=0;
              char e ; 
              for(;d<c;d++)
                 {
                    e = b.charAt(d);
                     if((e=='A')||(e=='E')||(e=='I')||(e=='O')||(e=='U'))  \\Used for letters at beginning of Sentence 
                          ++f;
                      if(((e=='a')||(e=='e')||(e=='i')||(e=='o')||(e=='u'))&&((d-1)==' ')&(d!=0))
                           ++f;
                   }
                System.out.print(f);
            }
      }

I will be happy if those lengthy if conditions is shortened.

The program's output is n't correct

For a given input, what do you receive and what do you expect? Please provide as much detail as possible

You code don't work because you forget of to write b.charAt(d-1). You wrote only (d-1).

                  if(((e=='a')||(e=='e')||(e=='i')||(e=='o')||(e=='u'))&&(b.charAt(d-1)==' ')&(d!=0))

You can reduce you code this way:

 
     void Input()throws IOException
     {
         BufferedReader a = new BufferedReader(new InputStreamReader(System.in));
         System.out.println("Enter your Sentence");
         String[] b = a.readLine().toLowerCase().split("[ ]+");
         int f = 0;
         for(String s: b)
         {
        	 if(s.matches("[aeiou].*"))
        		 f++;
         }
 
         System.out.println(f);
 
        }

In line

 String[] b = a.readLine().toLowerCase().split("[ ]+");

I divide the sentence in words and I passed all to lower case. The separator is one or more spaces.

In line

 if(s.matches("[aeiou].*"))

I use regular expression. If word start with vowels f is increment. The .* mean any caracter.

I was helped or confused?

>What about the startsWith(String prefix) method?

You can to use startsWith. But you have to use for each letter. For example:

 
 if(s.startsWith("a") || s.startsWith("e") || s.startsWith("i") || s.startsWith("o") || s.startsWith("u"))
    f++;

>Are you asking if each letter is a vowel or if each word begins with a vowel?

On my code I see if each word begins with a vowel.

>What exactly is that doing?

In a regular expression we have some rules, for examples:

[ ] means that the character is a space or \n or \r
[ ]+ means one or more (spaces or \n or \r)
[aeiou] means that the character is a or e or i or o or u
. means one any character
.* means zero or one or more any character

So

I use the regular expresssion ("[ ]+") for divide sentence in words. And I Use ("[aeiou].*") for match any word that begins with a or e or i or o or u follow of any character. How I divide this sentence in words each word don't have spaces.

understand?