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Thread: Array Code Help

  1. #1
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    Default Array Code Help

    public class Kitty {
     
        private String name;
        private int age;
     
        public Kitty(){
        }
     
        public void setName(String n){
            name = n;
        }
     
        public String getName(){
            return name;
        }
     
        public void setAge(int a){
            age = a;
        }
     
        public int getAge(){
            return age;
        }
    }

    The array myCats is an 8 element array of type Kitty that has already been declared and initialized. Write the expression(s) in the box below that prints to the console the name of the fourth Kitty if its age is strictly greater than the age of the fifth Kitty, and prints the name of the fifth Kitty otherwise:

    (Remember: the first element of an array is at index position 0).

    My code is
    int age4=myCats[3].getAge();
    int age5=myCats[4].getAge();
    if(age4>age5)
    {
    System.out.print(myCats[3].getName());


  2. #2
    Member vanDarg's Avatar
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    Default Re: Array Code Help

    And your question is?
    "Everything should be made as simple as possible, but not simpler."
    Asking Questions for Dummies | The Java Tutorials | Java Coding Styling Guide

  3. #3
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    Default Re: Array Code Help

    why isnt it working? this is the feedback i get
    Your code did not print the correct name given this input array:
    Name: Sylvester
    Age: 0
    Name: Sasha
    Age: 8
    Name: Toby
    Age: 2
    Name: Felix
    Age: 3
    Name: Toby
    Age: 7
    Name: Buddy
    Age: 10
    Name: Fuzzball
    Age: 13
    Name: Jasmine
    Age: 7
    Your code printed this name: ,
    the correct name is Toby.
    Remember, print the name of the 4th Kitty if it is strictly greater then the 5th Kit

  4. #4
    Member vanDarg's Avatar
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    Default Re: Array Code Help

    Make sure you implement an "else" statement
    Last edited by vanDarg; March 21st, 2011 at 04:46 PM.
    "Everything should be made as simple as possible, but not simpler."
    Asking Questions for Dummies | The Java Tutorials | Java Coding Styling Guide

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