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Thread: DFS in Graphs

  1. #1
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    Default DFS in Graphs

    This is the implementation of DFS using stacks, but when I try to run this it gives an infinite loop at the first vertex. Graph class has a array of nodes as it's attribute. The node class is used for both Vertices and Edges. I've tested whether the graph is read in correctly or not and it has been. I could provide the input file and the readFile method used to generate the graph. I don't know why it gets stuck in an infinite loop here.
    public static void dfs(Node start)
    {
    //DFS uses Stack data structure
    Stack s=new Stack();
    s.push(start);
    start.visited=true;
    System.out.println(start.item);
    while(!s.isEmpty())
    {
        Node n= (Node)s.peek();
                Node child=getUnvisitedChildNode(n);
        if(child!=null)
        {
            child.visited=true;
            System.out.println(child.item);
            s.push(child);
        }
     
        else
        {
            s.pop();
        }
    }
     
    }
     
    public static Node getUnvisitedChildNode(Node n){
    Node missing_child = new Node();
    Node counter = new Node(n.item);
    while(counter!=null){
         if (!counter.visited)
             missing_child = counter;
    counter = counter.next;
     
    }
     
     
    return missing_child;
    }
    Last edited by antislayer; April 24th, 2011 at 10:35 AM.


  2. #2
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    Default Re: DFS in Graphs

    I think I see a problem in getUnvisitedChildNode(), Is it possible for it to return a null value?

  3. #3
    Administrator copeg's Avatar
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    Default Re: DFS in Graphs

    Agree with JJeng. If getUnvisitedChildNode() never returns null, the code in dfs will always be adding another node to the stack, thus the while loop checking the stack size will never quit.

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