Thread: Checking Blurbs

Hi, finishing my first year of C.S., and now I'm stuck on my last homework problem. I need to check whether a user entered String is a Blurb. A Blurb is a Whoozit followed by one or more Whatzits. A Whoozit is the character ‘ x’ followed by zero or more ‘ y’s. A Whatzit is a ‘ q’ followed by either a ‘ z’ or a ‘ d’, followed by a Whoozit. It keeps returning false, even though it's true. I used the debugger to find out that it is returning false when it's checking whether the first whatzit is a "qd" or "qf." I'm typing in xqdx, and for some reason it's telling me that it isn't qd, I guess. The problem is in the isWhatzit() method.

import java.util.*;
 
public class CheckBlurb 
{
	static int count = 0;
 
	public static void main(String[] args) 
	{
		String userInput;
		Scanner scan = new Scanner(System.in);
 
		System.out.println("Enter a blurb.");
		userInput = scan.next();
 
		boolean isValid;
 
		int checkStart = isWhoozit(userInput);
 
		if(checkStart == 0)
		{
			isValid = false;
		}
		else
		{
			String nextCheck = (userInput.substring(checkStart));
			isValid = isWhatzit(nextCheck);
		}
 
		if(isValid == true)
		{
			System.out.println("Yep, that is a Blurb.");
		}
		else
		{
			System.out.println("Nope, not a Blurb, sorry.");
		}
 
	}
 
	public static int isWhoozit(String str)
	{
 
		if(str.charAt(count) == 'x')
		{
			count ++;
			while(str.charAt(count) == 'y')
			{
				count++;
			}
 
		}
		else
		{
			count = 0;
		}
		return count;
 
	}
 
	public static boolean isWhatzit(String str)
	{
		if(str.substring(0,1) != "qd" || str.substring(0,1) != "qz")
		{
			return false;
		}
 
		str = str.substring(2);
 
		int nextWhoozit = isWhoozit(str);
 
		if (nextWhoozit == 0)
		{
			return false;
		}
 
		else if (nextWhoozit >= str.length())
		{
			return true;
		}
 
		else
		{
			return isWhatzit(str.substring(nextWhoozit));
		}
	}
}

Right, I realized that and changed it. It worked, but backwards. Not really sure how to explain it, but I was able to make it work. Thanks for the reply.