Thread: Array Search Method

Thanks for taking the time to look at this code. Basically instead of printing out the row that the searched surname is on it prints out line[i][2] i++. How Can i fix this. The Array Size is line[6][5]. And When i search the Furthest surname (line[0][5])
it gives me an array out of bounds exception. Thanks you in advance for the help.

public void searchSurname(String[][] line){
 
        boolean found = false;
        Scanner scan=new Scanner(System.in);
        String searchKey=scan.nextLine();
        int column = 0;
        for(int i=0; i<6; i++){
                if(searchKey.equalsIgnoreCase(line[i][column])){
                        found = true;
                        column = i;
                }
        }
        if(found==true){
                System.out.println("Person is found!");
                for(int i=0; i<line.length;i++){
                        System.out.println(line[i][column]);
                }
        }else if(found==false){
                System.out.println("Person is not found");
        }

Can you please show the code where create and fill the 'String[][] line' array?

it gives me an array out of bounds exception

Please copy and paste the full text of the error message here.
It gives the bad index value and the source code line number where the error occurred.

Originally Posted by Kyuubi426

The Array Size is line[6][5]. And When i search the Furthest surname (line[0][5])

Remember that for an array of length N the last index is N-1.