Thread: Iterating a String

In the code for a loop that you posted, what variable is going to start at 0 and increment by one every time thru the loop?

Does the code you posted compile? length is a method not a variable in the String class

Java naming conventions: variable names start with lowercase letters: string1 vs String1

Also I'd recommend that you put a { at the end of the if statement and a } following the last line that you want to be in the loop. Align the ending } with the start of the if statement. Indent the code within the {}s.

I'm getting there slowly. I can have the loop counter as an actual parameter to itererate through a string object

DisplayLetter(String1.charAt(for (int count= 0; count < aString.length; count++));

but i'm getting illegal start of expression. What is my error , can any top java guy help on my code above so it runs ok.

Cheers.

That's an interesting construction of a statement.
Your previous post was almost there, you just had to put the loop index into the method call.
Now what have you done?
What does the API doc for the charAt() method say it takes for an argument?
Certainly not a for loop.
You could use an expression of some kind as the argument for charAt() as long as it returned the correct type of value. for loops are not expressions that return values.

Can you advise on the syntax how to put the loop index into the method call.

Thank you.

Replace the ? with count

Thanks Norm I've tried this and it displays only the last letter e.

I've tried this and it displays only the last letter

What did you try? I don't see any code.

for(int count = 0; count < aString.length(); count++)
DisplayLetter(aString.charAt(count));

This is painful. Do I have to ask you for the source line by line?
You don't show what the value of aString is or the complete output from your program.

Sorry,

String aString = new String();



aString = "bubble";

for(int count = 0; count < aString.length(); count++)
DisplayLetter(aString.charAt(count));

the out put is e

For the next lines of code I need to see: The DisplayLetter method.

Execute this code and see what is printed out:

      String aString = "bubble";
      for(int count = 0; count < aString.length(); count++) {
          System.out.println(count + " " + aString.charAt(count)); 
      } // end for(count)

Another scenario

String String1 = new String();

String1 = "bubble";

String1.charAt(0);
String1.charAt(1);
String1.charAt(2);
String1.charAt(3);
String1.charAt(4);
String1.charAt(5);

when I execute the above 6 lines individually the output corresponds to the index value.

I would like to output all the individual characters using the code below but I do not know what I am missing.... their is no output.

for (int count = 0; count < String1.length(); count++)
String1.charAt(count);

for (int count = 0; count < String1.length(); count++) 
  String1.charAt(count);

vs

for(int count = 0; count < aString.length(); count++)
   DisplayLetter(aString.charAt(count));

Why did you remove the call to the DisplayLetter() method?

The following line returns a char, but what does the compiler do with that returned value?????
String1.charAt(count);

Thank you Norm for your patience

for(int count = 0; count < aString.length(); count++)
{
DisplayLetter(aString.charAt(count));
}
I had missed out the curlys, program works now. thanks again, Goodnight.

I'm afraid there is a lot of magic going on here.

Did I miss the DisplayLetter method code posting, or is it Top Secret?